

Dividing Polynomials
Presentation
•
Mathematics
•
9th - 12th Grade
•
Medium
Standards-aligned
Shilaura Atkins
Used 6+ times
FREE Resource
16 Slides • 12 Questions
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Multiple Choice
Find the product:
(3x + 2)(2x + 4)
6x2 + 16x + 8
5x2 +11x + 6
5x2 + 16x + 6
6x2 + 11x + 8
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6
Multiple Choice
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Multiple Choice
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Multiple Choice
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Multiple Choice
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Multiple Choice
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by Tanner Howell
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This is a separate example for you to view. Notice that the remainder is written a bit differently in this problem.
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Multiple Choice
Divide:
(4x2 - 24x + 35) / (2x - 5)
2x - 7
2x - 12
2x + 12
2x + 7
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Multiple Choice
Find the quotient using long division
4x−2
4x+2
4x−2+3x−11
4x+2+3x−11
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Open Ended
Nancy Pi is a YouTube favorite of mine, so let's see how she approaches synthetic division. What do you think about Nancy Pi? If you like her explanations, follow her on YouTube.
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Shortcut way to divide polynomials
Uses the roots (not factor form) as the divisor
Uses the coefficients of the terms, and not the variables, as the dividend
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1. Change the factor form of the divisor to the root. (factor form is (x - 3), root is 3)
2. Write out the polynomial to be divided in descending form, writing in zeros for the terms that are missing. For example: x4 + 2x2 + 4 would be written as: x4 + 0x3 + 2x2 + 0x + 4
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3. Write out the coefficients only of the polynomial, including signs and including the 0's
4. Write the root to the left of the coefficients with a vertical bar between it and the coefficients and a horizontal line underneath the coefficients (like an upside-down division symbol)
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5. Bring the first coefficient down below the line, without doing anything to it
6. Multiply the coefficient by the root, and add the number to the next term.
7. Multiply the sum by the coefficient and add to the next term.
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Multiple Choice
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Multiple Choice
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Multiple Choice
2x2 - x + 3
2x3 - x2 + 3x
2x2 + 11x + 33 + 108/x+3
2x2 - 5x + 12

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