Chain Rule Parts Identification

​ CHAIN RULE

$$u=g\left(x\right)$$ ​ and $$y=h\left(u\right)$$

​ (a)   $$=$$ ​ (b)   $$\cdot$$ ​ (c)  

CHAIN RULE

$$u=g\left(x\right)\ \ and\ \ \ y=h\left(u\right)$$

FUNCTION

$$y=12\left(4x^5-9\right)^8$$

$$u=EXP1\ \ and\ \ y=EXP2$$

$$\frac{du}{dx}=EXP3\ \ and\ \ \frac{dy}{du}=EXP4$$

Submit $$EXP1$$

CHAIN RULE

$$u=g\left(x\right)\ \ and\ \ \ y=h\left(u\right)$$

FUNCTION

$$y=12\left(4x^5-9\right)^8$$

$$u=EXP1\ \ and\ \ y=EXP2$$

$$\frac{du}{dx}=EXP3\ \ and\ \ \frac{dy}{du}=EXP4$$

Submit $$EXP2$$

CHAIN RULE

$$u=g\left(x\right)\ \ and\ \ \ y=h\left(u\right)$$

FUNCTION

$$y=12\left(4x^5-9\right)^8$$

$$u=EXP1\ \ and\ \ y=EXP2$$

$$\frac{du}{dx}=EXP3\ \ and\ \ \frac{dy}{du}=EXP4$$

Submit $$EXP3$$

CHAIN RULE

$$u=g\left(x\right)\ \ and\ \ \ y=h\left(u\right)$$

FUNCTION

$$y=12\left(4x^5-9\right)^8$$

$$u=EXP1\ \ and\ \ y=EXP2$$

$$\frac{du}{dx}=EXP3\ \ and\ \ \frac{dy}{du}=EXP4$$

Submit $$EXP4$$

CHAIN RULE

$$u=g\left(x\right)\ \ and\ \ \ y=h\left(u\right)$$

FUNCTION

$$y=25\left(11x^{18}-23\right)^{15}$$

$$u=EXP1\ \ and\ \ y=EXP2$$

$$\frac{du}{dx}=EXP3\ \ and\ \ \frac{dy}{du}=EXP4$$

Submit $$EXP1$$

CHAIN RULE

$$u=g\left(x\right)\ \ and\ \ \ y=h\left(u\right)$$

FUNCTION

$$y=25\left(11x^{18}-23\right)^{15}$$

$$u=EXP1\ \ and\ \ y=EXP2$$

$$\frac{du}{dx}=EXP3\ \ and\ \ \frac{dy}{du}=EXP4$$

Submit $$EXP2$$

CHAIN RULE

$$u=g\left(x\right)\ \ and\ \ \ y=h\left(u\right)$$

FUNCTION

$$y=25\left(11x^{18}-23\right)^{15}$$

$$u=EXP1\ \ and\ \ y=EXP2$$

$$\frac{du}{dx}=EXP3\ \ and\ \ \frac{dy}{du}=EXP4$$

Submit $$EXP3$$

CHAIN RULE

$$u=g\left(x\right)\ \ and\ \ \ y=h\left(u\right)$$

FUNCTION

$$y=25\left(11x^{18}-23\right)^{15}$$

$$u=EXP1\ \ and\ \ y=EXP2$$

$$\frac{du}{dx}=EXP3\ \ and\ \ \frac{dy}{du}=EXP4$$

Submit $$EXP4$$

CHAIN RULE

$$u=g\left(x\right)\ \ and\ \ \ y=h\left(u\right)$$

FUNCTION

$$y=36\ \sqrt[3]{16x^{13}+19}$$

$$u=EXP1\ \ and\ \ y=EXP2$$

$$\frac{du}{dx}=EXP3\ \ and\ \ \frac{dy}{du}=EXP4$$

Submit $$EXP1$$ (no radicals)