A.5A - Exit Ticket: Solving one, two & three step equations

Authored by Chelsea Wasson

Mathematics

9th Grade

CCSS covered

Used 7+ times

A.5A - Exit Ticket: Solving one, two & three step equations

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MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$360=-20a$

380

-18

340

Tags

CCSS.6.EE.B.7

MATH RESPONSE QUESTION

2 mins • 1 pt

$26=n+10$
n =

$16$

Mathematical Equivalence

Tags

CCSS.6.EE.B.7

MATH RESPONSE QUESTION

2 mins • 1 pt

$-15=-16+v$
v =

$1$

Mathematical Equivalence

Tags

CCSS.6.EE.B.7

MATH RESPONSE QUESTION

2 mins • 1 pt

$8=-5+m$
m =

$13$

Mathematical Equivalence

Tags

CCSS.6.EE.B.7

MATH RESPONSE QUESTION

2 mins • 1 pt

$-102=6m$
m =

$-17$

Mathematical Equivalence

Tags

CCSS.6.EE.B.7

MATH RESPONSE QUESTION

2 mins • 1 pt

$\frac{p}{9}+10=11$
p =

$9$

Mathematical Equivalence

Tags

CCSS.7.EE.B.4A

MATH RESPONSE QUESTION

2 mins • 1 pt

$1+\frac{p}{1}=1$
p =

$0$

Mathematical Equivalence

Tags

CCSS.6.EE.B.7

MATH RESPONSE QUESTION

2 mins • 1 pt

$-17=7x+4$
x =

$-3$

Mathematical Equivalence

Tags

CCSS.7.EE.B.4A

MATH RESPONSE QUESTION

2 mins • 1 pt

$-4=\frac{x-7}{5}$
x =

$-13$

Mathematical Equivalence

Tags

CCSS.7.EE.B.4A

10.

MATH RESPONSE QUESTION

2 mins • 1 pt

$2x-5=7$
x =

$6$

Mathematical Equivalence

Tags

CCSS.7.EE.B.4A

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A.5A - Exit Ticket: Solving one, two & three step equations

360=−20a360=-20a360=−20a

26=n+1026=n+1026=n+10 n =

−15=−16+v-15=-16+v−15=−16+v v =

8=−5+m8=-5+m8=−5+m m =

−102=6m-102=6m−102=6m m =

p9+10=11\frac{p}{9}+10=119p​+10=11 p =

1+p1=11+\frac{p}{1}=11+1p​=1 p =

−17=7x+4-17=7x+4−17=7x+4 x =

−4=x−75-4=\frac{x-7}{5}−4=5x−7​ x =

2x−5=72x-5=72x−5=7 x =

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$360=-20a$

$26=n+10$
n =

$-15=-16+v$
v =

$8=-5+m$
m =

$-102=6m$
m =

$\frac{p}{9}+10=11$
p =

$1+\frac{p}{1}=1$
p =

$-17=7x+4$
x =

$-4=\frac{x-7}{5}$
x =

$2x-5=7$
x =