PCCP Practice Quiz 6.1 - 6.2

$$\left(x-2\right)^2+\left(y+3\right)^2=49$$  

$$\left(x+2\right)^2+\left(y-3\right)^2=7$$  

$$\left(x-2\right)^2+\left(y+3\right)^2=7$$  

$$\left(x-2\right)^2+\left(y+3\right)^2=\sqrt[]{7}$$  

$$\left(x+2\right)^2+\left(y-3\right)^2=\sqrt[]{7}$$  

$$\left(x+2\right)^2+\left(y-3\right)^2=49$$  

$$\left(x+2\right)^2+\left(y-3\right)^2=49$$  

$$\left(x+2\right)^2+\left(y-3\right)^2=7$$  

$$\left(x-2\right)^2+\left(y+3\right)^2=7$$  

$$\left(x-2\right)^2+\left(y+3\right)^2=\sqrt[]{7}$$  

$$\left(x+2\right)^2+\left(y-3\right)^2=\sqrt[]{7}$$  

$$\left(x-2\right)^2+\left(y+3\right)^2=49$$  

$$\left(x+6\right)^2+y^2=12$$  

$$\left(x-6\right)^2+y^2=12$$  

$$\left(x+6\right)^2+y^2=6$$  

$$x^2+\left(y+6\right)^2=2\ \sqrt[]{3}$$  

$$x^2+\left(y-6\right)^2=6$$  

$$x^2+\left(y+6\right)^2=12$$  

$$x^2+\left(y+6\right)^2=2\ \sqrt[]{3}$$  

$$\left(x+6\right)^2+y^2=2\ \sqrt[]{3}$$  

$$\left(0,\ 8\right)$$  

$$\sqrt[]{10}$$  

$$\left(0,\ -8\right)$$  

$$100$$  

$$\left(8,\ 0\right)$$  

$$10$$  

$$\left(-8,\ 0\right)$$  

$$5$$  

$$\left(-4,\ 3\right)$$  

$$5$$  

$$\left(4,\ -3\right)$$  

$$625$$  

$$\left(-3,\ 4\right)$$  

$$\sqrt[]{5}$$  

$$\left(3,\ -4\right)$$  

$$50$$  

$$\left(x-6\right)^2+\left(y+9\right)^2=121$$  

$$\left(x-6\right)^2+\left(y+9\right)^2=4$$  

$$\left(x-12\right)^2+\left(y+18\right)^2=4$$  

$$\left(x-12\right)^2+\left(y+18\right)^2=34$$  

$$\left(x-6\right)^2+\left(y+9\right)^2=19$$  

$$\left(6,\ -9\right)$$  

$$11$$  

$$\left(-12,\ 18\right)$$  

$$\sqrt[]{34}$$  

$$\sqrt[]{19}$$  

$$\left(-6,\ 9\right)$$  

$$\left(12,\ 18\right)$$  

$$2$$  

$$\left(x+5\right)^2+y^2=36$$  

$$\left(x+10\right)^2+y^2=21$$  

$$\left(x+5\right)^2+\left(y+\frac{11}{2}\right)^2=\frac{221}{4}$$  

$$\left(x-5\right)^2+\left(y+11\right)^2=0$$  

$$\left(x+10\right)^2+\left(y-11\right)^2=0$$  

$$\left(-5,\ 0\right)$$  

$$6$$  

$$\left(-10,\ 0\right)$$  

$$\left(-5,\ -\frac{11}{2}\right)$$  

$$0$$  

$$\left(-10,\ 11\right)$$  

$$\sqrt[]{21}$$  

$$\frac{\sqrt[]{221}}{2}$$  

$$\left(5,\ 11\right)$$  

$$\left(5,\ 0\right)$$