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Mathematics

9th Grade

CCSS covered

Used 41+ times

Inverse Trig Functions Note Check  + Unit Review
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21 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Since g(x)=sin⁡(x)g\left(x\right)=\sin\left(x\right)   is not one to one, it does not have an inverse.

True

False

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What test will you use to determine if a function is one-to-one?

Veetical Line Test

Horizontal Line Test

One-to-one Test

Function Domain-Range Test

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

True or False: arcsin⁡(x)\arcsin\left(x\right)   is another way to write sin⁡−1(x)\sin^{-1}\left(x\right)  .

TRUE!

FALSE!

Tags

CCSS.HSF.TF.B.7

4.

MULTIPLE CHOICE QUESTION

2 mins • 5 pts

Domain of function   sin⁡−1x is\sin^{-1}x\ is  

[−π2,π2]\left[-\frac{\pi}{2},\frac{\pi}{2}\right]  

(−π2,π2)\left(-\frac{\pi}{2},\frac{\pi}{2}\right)  

(−1,1)\left(-1,1\right)  

[−1,1]\left[-1,1\right]  

Tags

CCSS.HSF-BF.B.4D

5.

MULTIPLE SELECT QUESTION

2 mins • 1 pt

In which two quadrants is inverse sine defined?

Quadrant I

Quadrant II

Quadrant III

Quadrant IV

Answer explanation

Remember, the range of inverse sine is restricted from -pi/2 to pi/2 (only Quadrants I and IV!)

Tags

CCSS.HSF-BF.B.4D

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Which can be a restriction for the domain of y = cos x so the inverse cosine can be a function?

[−π2, π2]\left[-\frac{\pi}{2},\ \frac{\pi}{2}\right]

[0, π]\left[0,\ \pi\right]

(−π2, π2)\left(-\frac{\pi}{2},\ \frac{\pi}{2}\right)

[0, 2π]\left[0,\ 2\pi\right]

Tags

CCSS.HSF-BF.B.4D

7.

MULTIPLE CHOICE QUESTION

2 mins • 5 pts

Range of function   cos⁡−1x is\cos^{-1}x\ is  

[0, π]\left[0,\ \pi\right]  

(−π2,π2)\left(-\frac{\pi}{2},\frac{\pi}{2}\right)  

(−1,1)\left(-1,1\right)  

[−1,1]\left[-1,1\right]  

Tags

CCSS.HSF-BF.B.4D

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