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Mathematics

9th - 12th Grade

CCSS covered

Used 13+ times

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32 questions

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1.

MATCH QUESTION

2 mins • 5 pts

Match the following

sinθ

1csc⁡θ\frac{1}{\csc\theta}

secθ

sin⁡θcos⁡θ\frac{\sin\theta}{\cos\theta}

cotθ

1cos⁡θ\frac{1}{\cos\theta}

cscθ

1sin⁡θ\frac{1}{\sin\theta}

tanθ

cos⁡θsin⁡θ\frac{\cos\theta}{\sin\theta}

2.

MULTIPLE SELECT QUESTION

2 mins • 3 pts

Select all that are true

sin⁡2θ+cos⁡2θ=1\sin^2\theta+\cos^2\theta=1

cos⁡2=1−sin⁡2θ\cos^2=1-\sin^2\theta

sin⁡2θ=1−cos⁡2θ\sin^2\theta=1-\cos^2\theta

sin⁡2θ+1=−cos⁡2θ\sin^2\theta+1=-\cos^2\theta

sin⁡θ+cos⁡θ=12\sin\theta+\cos\theta=\frac{1}{2}

Tags

CCSS.HSF.TF.C.8

3.

MULTIPLE SELECT QUESTION

2 mins • 2 pts

Select all the correct variations of the following pythagorean identity:

1+cot⁡2θ=csc⁡2θ1+\cot^2\theta=\csc^2\theta

cot⁡2θ=csc⁡2θ−1\cot^2\theta=\csc^2\theta-1

1=csc⁡2θ−cot⁡2θ1=\csc^2\theta-\cot^2\theta

cot⁡2θ+csc⁡2θ=1\cot^2\theta+\csc^2\theta=1

cot⁡2θ−csc⁡2θ=1\cot^2\theta-\csc^2\theta=1

4.

MULTIPLE SELECT QUESTION

2 mins • 2 pts

Select all the correct variations of the following pythagorean identity:

1+tan⁡2θ=sec⁡2θ1+\tan^2\theta=\sec^2\theta

1=sec⁡2θ−tan⁡2θ1=\sec^2\theta-\tan^2\theta

tan⁡2θ=sec⁡2θ−1\tan^2\theta=\sec^2\theta-1

tan⁡2θ+sec⁡2θ=1\tan^2\theta+\sec^2\theta=1

sec⁡θ−tan⁡θ=1\sec\theta-\tan\theta=1

5.

MATH RESPONSE QUESTION

2 mins • 1 pt

sin⁡θ⋅csc⁡θ\sin\theta\cdot\csc\theta

11

Mathematical Equivalence

ON

6.

MATH RESPONSE QUESTION

2 mins • 1 pt

tan⁡θ⋅cot⁡θ\tan\theta\cdot\cot\theta

11

Mathematical Equivalence

ON

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

sin⁡θ\sin\theta

cos⁡θ\cos\theta

cos⁡(90o−θ)\cos\left(90^o-\theta\right)

−cos⁡θ-\cos\theta

Tags

CCSS.HSF.TF.C.9

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