Order of Operations

Authored by Kayla Heise

Mathematics

3rd Grade

CCSS covered

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10 questions

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FILL IN THE BLANKS QUESTION

15 mins • 2 pts

Solve the equation using PEMDAS: $3+8\left(4-2\right)-7$

(a)

Answer explanation

$3+8\left(4-2\right)-7$
= $3+8\left(2\right)-7$
= $3+16-7$
= $19-7$
= $12$

Tags

CCSS.7.NS.A.3

FILL IN THE BLANKS QUESTION

15 mins • 2 pts

Solve the equation using PEMDAS: $10+4\left(9+8\right)+12\div3-4$

(a)

Answer explanation

$10+4\left(9+8\right)+12\div3-4$
= $10+4\left(17\right)+12\div3-4$
= $10+68+4-4$
= $78+0$
= $78$

Tags

CCSS.7.NS.A.3

FILL IN THE BLANKS QUESTION

15 mins • 2 pts

Solve the equation using PEMDAS: $3^2-\left(9-5\right)+7\times3-8\div2$

(a)

Answer explanation

$3^2-\left(9-5\right)+7\times3-8\div2$
= $3^2-\left(4\right)+7\times3-8\div2$
= $9-4+7\times3-8\div2$
= $9-4+21-4$
= $5+17$
= $22$

Tags

CCSS.7.NS.A.3

FILL IN THE BLANKS QUESTION

15 mins • 2 pts

Solve the equation using PEMDAS: $\left(3\times5^2\div15\right)-\left(5-2^2\right)$

(a)

Answer explanation

$\left(3\times5^2\div15\right)-\left(5-2^2\right)$
= $\left(3\times25\div15\right)-\left(5-4\right)$
= $\left(75\div15\right)-\left(5-4\right)$
= $5-\left(5-4\right)$
= $5-1$
= $4$

Tags

CCSS.7.NS.A.3

MULTIPLE CHOICE QUESTION

15 mins • 4 pts

True or False: $3+2\left(6\times7\right)-3=2^2-2\left(7-5\right)$

True

False

Answer explanation

$3+2\left(6\times7\right)-3$
= $3+2\left(42\right)-3$
= $3+84-3$
= $87-3$
= $84$
$2^2-2\left(7-5\right)$
= $2^2-2\left(2\right)$
= $4-2\left(2\right)$
= $4-4$
= $0$

Tags

CCSS.5.OA.A.1

CCSS.5.OA.A.2

MULTIPLE CHOICE QUESTION

15 mins • 4 pts

True or False: $\left(18\div6\times5\right)-14\div7\ =\ 10-8\div4+\left(7-2\right)$

True

False

Answer explanation

$\left(18\div6\times5\right)-14\div7$
= $\left(3\times5\right)-14\div7$
= $\left(15\right)-14\div7$
= $15-2$
= $13$
$10-8\div4+\left(7-2\right)$
= $10-8\div4+5$
= $10-2+5$
= $8+5$
= $13$

Tags

CCSS.5.OA.A.1

CCSS.5.OA.A.2

MULTIPLE CHOICE QUESTION

15 mins • 4 pts

To make the following equation true, where should the parenthesis go?
$40-17-14+3=34$

$\left(40-17\right)-14+3=34$

$40-\left(17-14+3\right)=34$

$40-17-\left(14+3\right)=34$

$40-\left(17-14\right)+3=34$

Answer explanation

$40-\left(17-14+3\right)$
= $40-\left(3+3\right)$
= $40-\left(6\right)$
= $34$

Tags

CCSS.5.OA.A.1

CCSS.5.OA.A.2

MULTIPLE CHOICE QUESTION

15 mins • 4 pts

To make the following equation true, where should the parenthesis go?
$37-34+11-30=22$

$\left(37-34+11\right)-30=22$

$37-34+\left(11-30\right)=22$

$37-\left(34+11-30\right)=22$

$\left(37-34\right)+11-30=22$

Answer explanation

$37-\left(34+11-30\right)$
= $37-\left(45-30\right)$
= $37-\left(15\right)$
= $22$

Tags

CCSS.5.OA.A.1

CCSS.5.OA.A.2

OPEN ENDED QUESTION

15 mins • 4 pts

What error was made?
Step 1: $\left(24-10\right)+3^2\times8$
Step 2: $\left(14\right)+3^2\times8$
Step 3: $14+6\times8$
Step 4: $14+48\ =\ 62$

Evaluate responses using AI:

OFF

Answer explanation

$\left(24-10\right)+3^2\times8$
= $\left(14\right)+3^2\times8$
= $14+9\times8$
= $14+72$
= $86$

Tags

CCSS.5.OA.A.1

CCSS.5.OA.A.2

10.

OPEN ENDED QUESTION

15 mins • 4 pts

What error was made?
Step 1: $5+2\left(6+3\div3\right)$
Step 2: $5+2\left(9\div3\right)$
Step 3: $5+2\left(3\right)$
Step 4: $5+6=11$

Evaluate responses using AI:

OFF

Answer explanation

$5+2\left(6+3\div3\right)$
= $5+2\left(6+1\right)$
= $5+2\left(7\right)$
= $5+14$
= $19$

Tags

CCSS.7.NS.A.3

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Order of Operations

Solve the equation using PEMDAS: 3+8(4−2)−73+8\left(4-2\right)-73+8(4−2)−7 (a)

3+8(4−2)−73+8\left(4-2\right)-73+8(4−2)−7 = 3+8(2)−73+8\left(2\right)-73+8(2)−7 = 3+16−73+16-73+16−7 = 19−719-719−7 = 121212

Solve the equation using PEMDAS: 10+4(9+8)+12÷3−410+4\left(9+8\right)+12\div3-410+4(9+8)+12÷3−4 (a)

10+4(9+8)+12÷3−410+4\left(9+8\right)+12\div3-410+4(9+8)+12÷3−4 = 10+4(17)+12÷3−410+4\left(17\right)+12\div3-410+4(17)+12÷3−4 = 10+68+4−410+68+4-410+68+4−4 = 78+078+078+0 = 787878

Solve the equation using PEMDAS: 32−(9−5)+7×3−8÷23^2-\left(9-5\right)+7\times3-8\div232−(9−5)+7×3−8÷2 (a)

32−(9−5)+7×3−8÷23^2-\left(9-5\right)+7\times3-8\div232−(9−5)+7×3−8÷2 = 32−(4)+7×3−8÷23^2-\left(4\right)+7\times3-8\div232−(4)+7×3−8÷2 = 9−4+7×3−8÷29-4+7\times3-8\div29−4+7×3−8÷2 = 9−4+21−49-4+21-49−4+21−4 = 5+175+175+17 = 222222

Solve the equation using PEMDAS: (3×52÷15)−(5−22)\left(3\times5^2\div15\right)-\left(5-2^2\right)(3×52÷15)−(5−22) (a)

True or False: 3+2(6×7)−3=22−2(7−5)3+2\left(6\times7\right)-3=2^2-2\left(7-5\right)3+2(6×7)−3=22−2(7−5)

3+2(6×7)−33+2\left(6\times7\right)-33+2(6×7)−3 = 3+2(42)−33+2\left(42\right)-33+2(42)−3 = 3+84−33+84-33+84−3 = 87−387-387−3 = 848484 22−2(7−5)2^2-2\left(7-5\right)22−2(7−5) = 22−2(2)2^2-2\left(2\right)22−2(2) = 4−2(2)4-2\left(2\right)4−2(2) = 4−44-44−4 = 000

True or False: (18÷6×5)−14÷7 = 10−8÷4+(7−2)\left(18\div6\times5\right)-14\div7\ =\ 10-8\div4+\left(7-2\right)(18÷6×5)−14÷7 = 10−8÷4+(7−2)

To make the following equation true, where should the parenthesis go? 40−17−14+3=3440-17-14+3=3440−17−14+3=34

40−(17−14+3)40-\left(17-14+3\right)40−(17−14+3) = 40−(3+3)40-\left(3+3\right)40−(3+3) = 40−(6)40-\left(6\right)40−(6) = 343434

To make the following equation true, where should the parenthesis go? 37−34+11−30=2237-34+11-30=2237−34+11−30=22

37−(34+11−30)37-\left(34+11-30\right)37−(34+11−30) = 37−(45−30)37-\left(45-30\right)37−(45−30) = 37−(15)37-\left(15\right)37−(15) = 222222

What error was made?Step 1: (24−10)+32×8\left(24-10\right)+3^2\times8(24−10)+32×8 Step 2: (14)+32×8\left(14\right)+3^2\times8(14)+32×8 Step 3: 14+6×814+6\times814+6×8 Step 4: 14+48 = 6214+48\ =\ 6214+48 = 62

(24−10)+32×8\left(24-10\right)+3^2\times8(24−10)+32×8 = (14)+32×8\left(14\right)+3^2\times8(14)+32×8 = 14+9×814+9\times814+9×8 = 14+7214+7214+72 = 868686

What error was made?Step 1: 5+2(6+3÷3)5+2\left(6+3\div3\right)5+2(6+3÷3) Step 2: 5+2(9÷3)5+2\left(9\div3\right)5+2(9÷3) Step 3: 5+2(3)5+2\left(3\right)5+2(3) Step 4: 5+6=115+6=115+6=11

5+2(6+3÷3)5+2\left(6+3\div3\right)5+2(6+3÷3) = 5+2(6+1)5+2\left(6+1\right)5+2(6+1) = 5+2(7)5+2\left(7\right)5+2(7) = 5+145+145+14 = 191919

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Discover more resources for Mathematics

Solve the equation using PEMDAS: $3+8\left(4-2\right)-7$

(a)

$3+8\left(4-2\right)-7$
= $3+8\left(2\right)-7$
= $3+16-7$
= $19-7$
= $12$

Solve the equation using PEMDAS: $10+4\left(9+8\right)+12\div3-4$

(a)

$10+4\left(9+8\right)+12\div3-4$
= $10+4\left(17\right)+12\div3-4$
= $10+68+4-4$
= $78+0$
= $78$

Solve the equation using PEMDAS: $3^2-\left(9-5\right)+7\times3-8\div2$

(a)

$3^2-\left(9-5\right)+7\times3-8\div2$
= $3^2-\left(4\right)+7\times3-8\div2$
= $9-4+7\times3-8\div2$
= $9-4+21-4$
= $5+17$
= $22$

Solve the equation using PEMDAS: $\left(3\times5^2\div15\right)-\left(5-2^2\right)$

(a)

True or False: $3+2\left(6\times7\right)-3=2^2-2\left(7-5\right)$

$3+2\left(6\times7\right)-3$
= $3+2\left(42\right)-3$
= $3+84-3$
= $87-3$
= $84$
$2^2-2\left(7-5\right)$
= $2^2-2\left(2\right)$
= $4-2\left(2\right)$
= $4-4$
= $0$

True or False: $\left(18\div6\times5\right)-14\div7\ =\ 10-8\div4+\left(7-2\right)$

To make the following equation true, where should the parenthesis go?
$40-17-14+3=34$

$40-\left(17-14+3\right)$
= $40-\left(3+3\right)$
= $40-\left(6\right)$
= $34$

To make the following equation true, where should the parenthesis go?
$37-34+11-30=22$

$37-\left(34+11-30\right)$
= $37-\left(45-30\right)$
= $37-\left(15\right)$
= $22$

What error was made?
Step 1: $\left(24-10\right)+3^2\times8$
Step 2: $\left(14\right)+3^2\times8$
Step 3: $14+6\times8$
Step 4: $14+48\ =\ 62$

$\left(24-10\right)+3^2\times8$
= $\left(14\right)+3^2\times8$
= $14+9\times8$
= $14+72$
= $86$

What error was made?
Step 1: $5+2\left(6+3\div3\right)$
Step 2: $5+2\left(9\div3\right)$
Step 3: $5+2\left(3\right)$
Step 4: $5+6=11$

$5+2\left(6+3\div3\right)$
= $5+2\left(6+1\right)$
= $5+2\left(7\right)$
= $5+14$
= $19$