Law of Sines

find side c using pythagorean theorem

Set up a proportion to find angle C

Set up a proportion to find angle B

Set up a proportion to find angle A

$$\sin A=\frac{28\sin27}{18}$$  

$$\sin^{-1}\left(\frac{28\sin27}{18}\right)$$  

$$\sin\left(\frac{28\sin27}{18}\right)$$  

$$\sin^{-1}\left(\frac{18\sin27}{28}\right)$$  

$$\angle A_1-90\degree$$   

hope you can see someone's paper to steal their answer 

$$180-\angle A_1=\angle A_2$$   

use a law of sine proportion 

$$\frac{18}{\sin108.1}=\frac{c}{\sin27}$$  

$$\frac{18}{\sin27}=\frac{c}{108.1}$$  

$$\frac{18}{27}=\frac{c}{108.1}$$  

$$\frac{18}{\sin27}=\frac{c}{\sin108.1}$$  

I want to cry! But with more practice I will cry less :)

I feel better now but I need more practice.

Still iffy :/ but I know that with extra practice I'll be good to go.

I am an expert but I will welcome the opportunity for extra practice.