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  5. Riemann's Sum And Summation Notation (11/10): Check For Understanding

Riemann's Sum and Summation Notation (11/10): Check for Understanding

Authored by Sherri Morrisey

Mathematics

12th Grade

CCSS covered

Used 8+ times

Riemann's Sum and Summation Notation (11/10): Check for Understanding
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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

∫25(x3+3)dx\int_2^5\left(x^3+3\right)dx  as limit of a sum is equivalent to

lim⁡n→∞∑i=1n[(2+3in)3+3]1n\lim_{n\rightarrow\infty}\sum_{i=1}^n\left[\left(2+\frac{3i}{n}\right)^3+3\right]\frac{1}{n}  

lim⁡n→∞∑i=1n[(2+3in)3+3]3in\lim_{n\rightarrow\infty}\sum_{i=1}^n\left[\left(2+\frac{3i}{n}\right)^3+3\right]\frac{3i}{n}  

lim⁡n→∞∑i=1n[(3in)3+3]3n\lim_{n\rightarrow\infty}\sum_{i=1}^n\left[\left(\frac{3i}{n}\right)^3+3\right]\frac{3}{n}  

lim⁡n→∞∑i=1n[(2+3in)3+3]3n\lim_{n\rightarrow\infty}\sum_{i=1}^n\left[\left(2+\frac{3i}{n}\right)^3+3\right]\frac{3}{n}  

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

∫0πcos⁡xdx \int_0^{\pi}\cos xdx\  as limit of a sum is equivalent to

lim⁡n→∞∑i=1n[cos⁡(πin)]in\lim_{n\rightarrow\infty}\sum_{i=1}^n\left[\cos\left(\frac{\pi i}{n}\right)\right]\frac{i}{n}  

lim⁡n→∞∑i=1n[cos⁡(in)]in\lim_{n\rightarrow\infty}\sum_{i=1}^n\left[\cos\left(\frac{i}{n}\right)\right]\frac{i}{n}  

lim⁡n→∞∑i=1n[cos⁡(πin)]πn\lim_{n\rightarrow\infty}\sum_{i=1}^n\left[\cos\left(\frac{\pi i}{n}\right)\right]\frac{\pi}{n}  

lim⁡n→∞∑i=1n[cos⁡(in)]πn\lim_{n\rightarrow\infty}\sum_{i=1}^n\left[\cos\left(\frac{i}{n}\right)\right]\frac{\pi}{n}  

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

lim⁡n→∞∑i=1n[(5in)2+5in+1]5n\lim_{n\rightarrow\infty}\sum_{i=1}^n\left[\left(\frac{5i}{n}\right)^2+\frac{5i}{n}+1\right]\frac{5}{n}  in integral notation would be 

∫05(x2+x+1)dx\int_0^5\left(x^2+x+1\right)dx  

∫56(x2+x+1)dx\int_5^6\left(x^2+x+1\right)dx  

∫01((5x)2+5x+1)dx\int_0^1\left(\left(5x\right)^2+5x+1\right)dx  

∫010(x22+x2+1)dx\int_0^{10}\left(\frac{x^2}{2}+\frac{x}{2}+1\right)dx  

4.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

lim⁡n→∞∑i=1n[2+3+4in]4n\lim_{n\rightarrow\infty}\sum_{i=1}^n\left[2+\sqrt{3+\frac{4i}{n}}\right]\frac{4}{n}  in integral notation would be 

∫37(2+x)dx\int_3^7\left(2+\sqrt{x}\right)dx  

∫04(2+x)dx\int_0^4\left(2+\sqrt{x}\right)dx  

∫37(2x+x)dx\int_3^7\left(2x+\sqrt{x}\right)dx  

∫37(2+3+x)dx\int_3^7\left(2+\sqrt{3+x}\right)dx  

5.

FILL IN THE BLANKS QUESTION

30 sec • 1 pt

Media Image

Evaluate

(a)  

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Sketch the function g(x)=4+x−3g\left(x\right)=4+\sqrt{x-3}  . Then approximate  A(g, 5≤x≤8)A\left(g,\ 5\le x\le8\right)  
 by both using six right endpoint rectangles and six left endpoint rectangles. Write both of the sums using sigma notation.

Left endpoint:  12∑n=16(4+(0.5n+5)−3)≈17.771\frac{1}{2}\sum_{n=1}^6\left(4+\sqrt{\left(0.5n+5\right)-3}\right)\approx17.771  

Right endpoint: 12∑n=05(4+(0.5n+5)−3)≈17.360\frac{1}{2}\sum_{n=0}^5\left(4+\sqrt{\left(0.5n+5\right)-3}\right)\approx17.360  

Left endpoint:  12∑n=05(4+(0.5n)−3)≈17.360\frac{1}{2}\sum_{n=0}^5\left(4+\sqrt{\left(0.5n\right)-3}\right)\approx17.360  
Right endpoint:  12∑n=16(4+(0.5n)−3)≈17.771\frac{1}{2}\sum_{n=1}^6\left(4+\sqrt{\left(0.5n\right)-3}\right)\approx17.771  

Left endpoint:  12∑n=05(4+(0.5n+5)−3)≈17.360\frac{1}{2}\sum_{n=0}^5\left(4+\sqrt{\left(0.5n+5\right)-3}\right)\approx17.360

Right endpoint:  12∑n=16(4+(0.5n+5)−3)≈17.771\frac{1}{2}\sum_{n=1}^6\left(4+\sqrt{\left(0.5n+5\right)-3}\right)\approx17.771  

Left endpoint:  12∑n=16(4+(0.5n)−3)≈17.360\frac{1}{2}\sum_{n=1}^6\left(4+\sqrt{\left(0.5n\right)-3}\right)\approx17.360  
Right endpoint:  12∑n=05(4+(0.5n)−3)≈17.771\frac{1}{2}\sum_{n=0}^5\left(4+\sqrt{\left(0.5n\right)-3}\right)\approx17.771  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What statement best describes the Riemann Sum?

4 intervals, with heights using middle values

4 intervals, with heights using left values

5 intervals, with heights using middle values

5 intervals, with heights using right values

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