CPM CCG 10.2.1-10.2.3 Conditional Probability Review

P(A∩B) = 0

P(A|B) = 0

P(A∪B) = 0

P(A) + P(B) = 1

P(A∩B) = 0

P(A|B) = P(A)

P(A∪B) = 0

P(A) + P(B) = 1

Intersection of event A and B

Union of event A and B

Universal event

Union and Intersection of event A and B

all the elements in event A and set B.

the common elements in event A and set B.

all the elements in event A but not in event B.

all the elements in event B but not in event A.

$\frac{1}{5}$

$\frac{8}{25}$

$\frac{12}{25}$

$\frac{4}{5}$

0.69

0.32

0.426

2.231

Yes, because P(S) is the same as P(S|CS).

No, because P(S) is not the same as P(S|CS).

Yes, because P(S) is the same as P(CS|S).

No, because P(S) is not the same as P(CS|S).