f'(x) = 3x² + 2x + 1

f'(x) = 3x²

f'(x) = 2x

Não existe

$$-1$$  

$$\frac{\left(-x^2+2x\right)}{x^2}$$  

$$\frac{1}{x^2}$$  

$$-\frac{1}{x^2}$$  

Nenhuma das opções é correta

$$\frac{\text{d}y}{\text{d}x}=8x^{-5}+4x$$  

$$\frac{\text{d}y}{\text{d}x}=-8x^{-5}+4$$  

$$\frac{\text{d}y}{\text{d}x}=-8x^{-4}+4$$  

$$\frac{\text{d}y}{\text{d}x}=8x^{-4}+4x$$  

$$\frac{\text{d}y}{\text{d}x}=2x^5+6x^2$$  

$$\frac{\text{d}y}{\text{d}x}=10x^6+6x$$  

$$\frac{\text{d}y}{\text{d}x}=10x^4-12$$  

$$\frac{\text{d}y}{\text{d}x}=10x^4+12x$$  

$$h´\left(x\right)=3xe^x$$  

$$h´\left(x\right)=e^{3x}$$  

$$h´\left(x\right)=3e^x$$  

$$h´\left(x\right)=\frac{e^x}{3}$$  

$$sen\ x\ -x\ .\ \cos\ x$$  

$$\cos\ x$$  

$$1\ +\ \cos\ x$$  

$$sen\ x\ +\ x.\ \cos\ x$$  

$$1+\ sen\ x$$

$$8$$  

$$8x.\ln\ x+4x$$  

$$8x\ .\ \frac{1}{x}$$  

$$8x\ .\ \ln\ x$$  

Nenhuma das opções está correta

$$\frac{1}{\sqrt{x}}$$  

$$2\sqrt{x}$$  

$$\frac{1}{2\sqrt{x}}$$  

$$\frac{\sqrt{x}}{2}$$  

Nenhuma das opções está correta

$$\frac{\text{d}g}{\text{d}x}=\cos\ x+sen\ x$$  

$$\frac{\text{d}g}{\text{d}x}=\cos x-sen\ x$$  

$$\frac{\text{d}g}{\text{d}x}=0$$  

$$\frac{\text{d}g}{\text{d}x}=2\cos\ x$$  

12x+5

12x

12x-5

6x+4

tan²(x)

sen²(x)

cos²(x)

sec²(x)

x²sen(x) + 2xcos(x)

2xcos(x) + x²sen(x)

2xsen(x) - x²cos(x)

2xsen(x) + x²cos(x)

f'(x) = ln(x) + 2x

f'(x) = 1/x - 2x

f'(x) = ln(x) - 2x

f'(x) = 1/x + 2x