Подготовка к экзамену по алгебре

2

3

5

1

4

$$\left(-\infty;-2\right)\cup\left(-1;6\right)\cup\left(6;+\infty\right)$$

$$\left(-\infty;-1\right)\cup\left(1;6\right)\cup\left(6;+\infty\right)$$

$$\left(-\infty;-1\right)\cup\left(-1;6\right)\cup\left(6;+\infty\right)$$

$$\left(-\infty;1\right)\cup\left(1;6\right)\cup\left(6;+\infty\right)$$

$$\left(-\infty;-1\right)\cup\left(-1;6\right)\cup\left(6;9\right)$$

$$\frac{m}{n}-7=\frac{m-n}{7n}$$

$$\frac{m}{n}-7=\frac{m-7n}{7n}$$

$$\frac{m}{n}-7=\frac{m-7n}{n}$$

$$\frac{m}{n}-7=\frac{m-7}{n}$$

 6х¹⁰ -6х²у⁴

-8х²у⁴

х¹⁰-6х²у⁴

6х¹⁰-9у⁴

2х⁵-6ху²

$$\frac{1}{7}$$  

$$7$$  

$$-\frac{1}{7}$$  

$$-7$$  

$$\frac{n-2m}{n^{2^{ }}-2nm+4m^2}$$

$$\frac{n+m}{n^{2^{ }}-2nm+4m^2}$$

$$\frac{n+2m}{n^{2^{ }}-nm+4m^2}$$

$$\frac{n+2m}{n^{2^{ }}-2nm+4m^2}$$

$$\frac{n+m}{n^{2^{ }}-2nm+4m^2}$$

10

-5

8

11

12

$$\frac{1}{c}:c=1$$

$$\frac{1}{c}:c=\frac{1}{c^{2\ }}$$

$$\frac{1}{c}:c=\frac{1}{2c}$$

$$\frac{1}{c}:c=c^2$$

150⁰

360⁰

420⁰

320⁰

300⁰

$$\left(-\infty;0\right)$$  

$$\left(8;+\infty\right)$$  

$$\left(0;8\right)$$  

$$\left(-\infty;8\right]$$  

$$\left(-\infty;-8\right)$$  

$$х^3+12х\le0$$

$$5х^2-2х^4+7<0$$

$$\left(5х-1\right)\left(5х+1\right)+\left(5х+2\right)^2\ge0$$

$$\left(х-3\right)\left(х+2\right)+2>х\left(х-4\right)$$

6х $$\le12$$

$$a^4b$$

$$a^5b$$

$$a^6b$$

$$a^7b$$

$$a^8b$$

$$\frac{bt}{2}$$  

$$\frac{t}{2}$$  

$$\frac{2t}{b}$$  

$$\frac{t}{2b}$$  

$$2bt$$  

120

180

210

240

280

1 и 2

1 и 3

2 и 3

1 и 4

2 и 4

$$5x^2-3x+4=0$$  

$$x^2-7x+0,2=0$$  

$$-\frac{1}{3}x^2+2x+1=0$$  

$$3x+x^2+4=0$$