Final Exam Review: Unit 3 (Rational Functions)

y = 0

y = -2

y = 2

There isn't one

$$y=\frac{1}{2}$$  

y = -2

y = 2

y = 0

D : $$\left(-\infty,-3\right)\cup\left(-3,\infty\right)$$ R: $$\left(-\infty,1\right)\cup\left(1,\infty\right)$$

D : $$\left(-\infty,1\right)\cup\left(1,\infty\right)$$ R: $$\left(-\infty,-3\right)\cup\left(-3,\infty\right)$$

D : $$\left(-\infty,3\right)\cup\left(3,\infty\right)$$ R: $$\left(-\infty,-1\right)\cup\left(-1,\infty\right)$$  

D: $$\left(-\infty,-1\right)\cup\left(-1,\infty\right)$$ R: $$\left(-\infty,3\right)\cup\left(3,\infty\right)$$

$$y=\frac{1}{x-3}$$  

$$y=\frac{1}{x+3}$$  

$$y=\frac{1}{3}$$  

$$y=\frac{3}{x}$$  

(0,2)

-6, 1

$$\ \frac{1}{3}$$

$$\left(0,-\frac{1}{3}\right)$$

All real numbers

All real numbers except where the denominator is zero

Only positive real numbers

Only negative real numbers

Crossing the x-axis

An absence of dirt.

Crossing a vertical asymptote.

A factor that cancels out.

x = -5

x = -5 and x = -3

y = 0

x = -3

x = -5 and x = 7

x = 3 and x = 4

x = 3 and x = -5

There are no vertical asymptotes

True

False

x=-1/2 and x=3

x=-1/2

x=1/2 and x = -3

x=1/2

x=7 and x = -4

x = 7

x = -7

x = -7 and x = 4

No hole

$$\left(3,\ \frac{12}{7}\right)$$  

$$\left(-3,\ 6\right)$$  

$$\left(-3,\ -6\right)$$  

No horizontal Aysmptote

y = 5

y = 1/5

y = 0

x = 1

x = 5

x = -5

x = 0