Equation of a Circle

(x – 2)² + (y + 4)² = 4

(x + 2)² + (y – 4)² = 4

(x – 2)² + (y + 4)² = 16

(x + 2)² + (y – 4)² = 16

(x - ^7)^2 + y^2 = 9

x^2 + (y -7)^2 = 9

(x - 7)^2 + y^2 = 3

x^2 + (y -7)^2 = 3

(2, 2)

(2, -2)

(0, 0)

(-2, 2)

2

6

3

5

(x+2) + (y-2) = 9

(x+2) + (y+2) = 9

(x+1) + (y+1) = 3

(x+1) + (y+1) = 3

(-5, 10)

(5, -10)

(5, 10)

(-5, -10)

$$\left(x-5\right)^2+\left(y-3\right)^2=2$$

$$\left(x-5\right)^2+\left(y-3\right)^2=4$$

$$\left(x+5\right)^2+\left(y+3\right)^2=2$$

$$\left(x+5\right)^2+\left(y+3\right)^2=4$$

$$x^2+\left(y+3\right)^2=2.5$$

$$x^2+\left(y-3\right)^2=5$$

$$x^2+\left(y+3\right)^2=25$$

$$x^2+\left(y-3\right)^2=25$$

$$\left(x-4\right)^2+y^2=9$$

$$\left(x+4\right)^2+y^2=9$$

$$\left(x-4\right)^2+y^2=36$$

$$\left(x+4\right)^2+y^2=36$$

$$\left(x-8\right)^2+y^2=6$$  

$$\left(x-8\right)^2+y^2=36$$  

$$\left(x-8\right)^2+y=6$$  

$$\left(x-8\right)^2+y^2=\sqrt[]{6}$$  

$$\left(x+3\right)^2+\left(y-4\right)^2=49$$  

$$\left(x-3\right)^2+\left(y+4\right)^2=49$$  

$$\left(x-3\right)^2+\left(y+4\right)^2=7$$  

$$\left(x+3\right)^2+\left(y-4\right)^{2\ }=7$$  

$$\left(x-3\right)^2+\left(x-5\right)^2=12$$  

$$\left(x-3\right)^2+\left(y-5\right)^2=144$$  

$$\left(x+3\right)^{2\ }+\left(x+5\right)^2=144$$  

$$\left(x+3\right)^2+\left(y+5\right)^2=12$$  

$$\left(x+5\right)^2+\left(x+6\right)^2=16$$  

$$\left(x-5\right)^2+\left(y-6\right)^2=16$$  

$$\left(x-5\right)^2+\left(y-6\right)^2=4$$  

$$\left(x+5\right)^2+\left(x+6\right)^2=4$$