Zero Product Property Lesson

Presentation

•

Mathematics

•

11th Grade

•

Hard

Joseph Anderson

FREE Resource

3 Slides • 14 Questions

Solving Polynomial Functions:
The Zero Product Property

Multiple Choice

Factor:

x² + 11x + 24

(x + 6)(x + 4)

(x + 12)(x + 2)

(x - 8)(x - 3)

(x + 8)(x + 3)

Multiple Choice

What are the factors of 3x²-17x+10

(x-5)(3x-2)

(x+5)(3x+2)

(3x-5)(x-2)

(x+5)(3x-2)

Multiple Choice

Find the factors of 5x²+20x+20

5(x+2)(x+2)

5(x-2)(x-2)

5(x+2)(x-2)

(5x+2)(x+2)

Zero Product Property

Steps:
1. Make sure polynomial is in standard form=0
2. Factor the polynomial completely.
3. Set each factor=0 and solve.
4. Write your answers as a solution set.
Here is a video

Multiple Choice

Solve for the values of x:
(x - 3)(x + 6) = 0

{ -3, -6 }

{ 3, -6 }

{ -3, -6 }

{ 3, 6 }

Multiple Choice

Factor Completely:
3x² + 18x +15
Hint: Factor GCF first.

3(x² + 6x + 5)

(x + 5)(x + 1)

3(x + 5)(x + 1)

Prime

Multiple Choice

Solve:

3x² + 18x +15 = 0

Hint: Factor GCF first.

x = 3, 2

x = 5, 1

x = -5, -1

x = -3, -2

Multiple Choice

Factor Completely:

x² - 49

(x - 7)(x - 7)

(x - 49)(x + 1)

(x - 14)(x + 14)

(x - 7)(x + 7)

Multiple Choice

Solve:

x² - 49 = 0

x = -7, x = 7

x = -7

x = 7

x = -7, x = 1

Multiple Choice

Solve: $\left(5x+4\right)\left(x-2\right)=0$

x = -4/5, x = 2

x = 2, x = -4

x = -2, x = 4

x = 0, x = 2

Multiple Choice

Solve: $2x^2-15=x$

Remember to rearrange the equation into standard form=0.

$x=-\frac{5}{2}$ and $x=3$

$x=\frac{5}{2}$ and $x=-3$

$x=\frac{5}{2}$ and $x=3$

$x=-\frac{5}{2}$ and $x=-3$

Multiple Choice

Solve:

k² - 2k = 24

k = -4, 6

k = -4, -6

k = -6, 1

k = 4, -6

Multiple Choice

Solve: $x^2-5x+6=0$

x = 2, x = 3

x = 0, x = 5

x = -2, x = -3

x = 1, x = 4

Multiple Choice

Solve: $-4k^2-8k-3=-3-5k^2$

k = 2

k = 4

k = 0 or k = 8

k = -1

Multiple Choice

Solve: $3b^3-4b^2-27b=-36$

b = 3, 4/3

b = -3, -9

b = 3, 9

b = 3, -3, 4/3

Solving Polynomial Functions:
The Zero Product Property

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