

Nuclear Chemistry
Presentation
•
Science
•
9th Grade
•
Hard
Joseph Anderson
FREE Resource
9 Slides • 8 Questions
1
By Mihir Paranjape
2
Nuclear | Chemical |
|---|---|
Nucleus | Electrons |
Hight Temp and Pressure | Normal Conditions |
New Elements/Isotopes | Compounds |
Large Amount of Energy | Smaller Amount of Energy |
Nuclear Fission, Fusion, Radioactive Decay | Combustion, Acid Base, Oxidation, Biochemical, Manufacturing compounds etc. |
3
Larger Nucleii are Unstable, these achieve stability by losing energy or particles and become lighter and more stable.
This process is called Radioactive Decay.
Radioactive Decays are represented by Nuclear Reactions.
To Balance Nuclear reactions, you have to balance
Mass Number
Atomic Number
4
Radioactive decays are defined based on particles emitted. e.g.
Alpha: He42 nucleus
Beta: Electron 0-1e
Gamma: No particles are emitted. High energy radiation.
Positron: 01e
Electron Capture: Capture of electron.
5
Alpha Particle (α) is emitted.
e.g
23892U He42 + 238-4=23492-2=90
Look up element with atomic number of 90, it is Th, so product is
23490Th
6
Alpha Particle (β) is emitted.
e.g
23892U e0-1 + 238-0=23892--1=93
Look up element with atomic number of 93, it is Np, so product is
23893Np
7
Gamma Rays (γ) are emitted. These have no particles
e.g
23892U γ + 238-0=23892-0=92
So there is no change in the nucleus
23892U
8
Multiple Choice
emitted helium nucleus
positron
radioactivity
alpha particle
gamma radiation
beta particle
9
Multiple Choice
10
Multiple Choice
11
Multiple Choice

12
Multiple Choice

13
Multiple Choice
After one ____________ of a radioactive element, half of the original radioactive material remains.
half-life
cycle
decay
14
Multiple Choice
15
Alpha Particle (β) is emitted.
e.g
23892U e0-1 + 238-0=23892--1=93
Look up element with atomic number of 93, it is Np, so product is
23893Np
16
Multiple Choice
17
Gamma Rays (γ) are emitted. These have no particles
e.g
23892U γ + 238-0=23892-0=92
So there is no change in the nucleus
23892U
By Mihir Paranjape
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