Introduction to Enthalpy

room temp of 25 degrees Celsius and 1 atm of pressure

zero enthalpy and zero molarity

no reaction

freezing temp of zero degrees Celsius and zero atm of pressure

the enthalpy change in which one mole of a compound dissolves in water

the enthalpy change in which one mole of a compound is decomposed into its elements

the enthalpy change in which one mole of a compound is made from its elements

page 1,088 of the textbook

in the senior parking lot

posted on Canvas

in the nucleus of the atom

60.75

-705.6

-271.9

0

60.75

-705.6

-271.9

0

60.75

33.84

-271.9

0

H₂ (g)

Hg (s)

CO₂ (g)

H₂O (l)

Br₂ (l)

exactly 1 mole of a compound

exactly 1 mole of an element

multiple moles of a compound

multiple moles of an element

Na (s) + Cl (s) --> NaCl (s)

2Na (s) + Cl₂ (g) --> 2 NaCl (s)

Na (s) + 1/2 Cl₂ (g) --> NaCl (s)

Na (g) + Cl₂ (g) --> NaCl (s)

S (s) + 3/2 O₂(g) --> SO₃ (g)

SO₃ (g) --> S (s) + 3/2 O₂(g)

S (s) + 3 O(g) --> SO₃ (g)

Pb(NO₃)₂ (s)  $$\longrightarrow$$  Pb (s) + 2 NO₃^-(aq)

Pb (s) + 2 NO₃^-(aq) $$\longrightarrow$$   Pb(NO₃)₂ (s)

Pb(s) + N₂ (g) + 3 O₂ (g)  $\longrightarrow$   Pb(NO₃)₂ (s)

Pb(NO₃)₂ (s)  $\longrightarrow$   Pb(s) + N₂ (g) + 3 O₂ (g)

3(-393.5) + 4(-285.83) - ((-103.85) +5(0)) kJ

(-103.85) +5(0) - (3(-393.5) + 4(-285.83)) kJ

(-285.83) +5(103.85) - (3(-393.5) + 4(-285.83)) kJ

3(-285.83) +4(103.85) - (5(-393.5) + 5(-285.83)) kJ

^-924.7 - (-601.8 + ^-285.83) kJ

^-285.83 + 2 (452.4) - (3 (297.4) + ^-141) kJ

-601.8 + ^-285.83 - (^-924.7) kJ

1(0) + 4(9.66) - (9.66 + 4(-241.82)) kJ

1(0) + 4(-241.82) - (9.66 + 4(0)) kJ

1(0) + 4(463.3) - (0 + 285.3) kJ

^-910.9 + 4(^-92.3) - (^-640.1+ 2(^-285.83))

^-640.1+ 2(^-285.83) - (910.9 + 4(^-92.3))

^-145.5 + 4(^-35.5) - (^-336.9+ 2(^-850.7))