AP Calculus District CA Review

$$h'\left(x\right)=\frac{5}{3}x^{-2}-f'\left(x\right)$$

$$h'\left(x\right)=-\frac{15}{x^4}-f'\left(x\right)$$

$$h'\left(x\right)=-\frac{15}{x^2}-f'\left(x\right)$$

$$h'\left(x\right)=f'\left(x\right)\cdot g'\left(x\right)$$

$$h'\left(x\right)=f'\left(x\right)\cdot g\left(x\right)+g'\left(x\right)\cdot f\left(x\right)$$

$$h'\left(x\right)=\frac{\left(f'\left(x\right)\cdot g\left(x\right)-g'\left(x\right)\cdot f\left(x\right)\right)}{\left(g\left(x\right)\right)^2}$$

That's impossible, we haven't learned that technique.

$$3\left(g'\left(x\right)\right)^3$$

$$12x^3\left(g'\left(x\right)\right)$$

$$12\left(g\left(x\right)\right)^3\left(g'\left(x\right)\right)$$

$$12\left(g'\left(x\right)\right)^3-5$$