Angle & Perpendicular Bisectors

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Each new angle measures 15°. Multiply by 2 to find the original, larger angle.

15° × 2 = 30°

So, the original angle measured 30°.

The Angle Bisector Theorem states that a point is on the bisector of an angle if and only if it is in the interior of the angle and is equidistant from the sides of the angle.

Z is on the angle bisector of ∠WXY if and only if it is in the interior of ∠WXY and WZ

≅YZ

.

Look at the Diagram. Since m∠GHJ=m∠IHJ=66°, 

HJ bisects ∠GHI.

Therefore, GJ≅IJ

 by the Angle Bisector Theorem.

So, I=G=49.

The Perpendicular Bisector Theorem 

states that a point is on the perpendicular bisector of a segment if and only if it is equidistant from the endpoints of the segment.

B is on the perpendicular bisector of AC if and only if AB≅BC

.

Since UV=VW=54, V is equidistant from the endpoints of UW. Therefore, V lies on the perpendicular bisector of UW by the Perpendicular Bisector Theorem.

Since V is on the perpendicular bisector of UW and ∠VXW is a right angle, VX is the perpendicular bisector of UW.

So, UX=WX=35 and UW=2(35)=70.

Since ∠TSU is a right angle and S=S=65, SU is the perpendicular bisector of TV.

Therefore, TU≅UV

 by the Perpendicular Bisector Theorem.

So, U=T=98.