Precalculus Roots of Polynomial - 01/10/24

Presentation

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Mathematics

•

12th Grade

•

Medium

Olutope Aghedo

Used 3+ times

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0 Slides • 15 Questions

Multiple Choice

Solve by using Rational Root Theorem:
x³ + 3x² - 6x - 8 = 0

-4, -1, 2

-4, -1, ±√2

1, 2, 4

4,-1,√2

Multiple Choice

Find all zeros.

x= 3,1,1/3

x= -3, -1, -1/3

x = -3, 1, 1/3

x = 3, -1, -1/3

Multiple Choice

Find the zeros of the polynomial given one factor.

X= 3,4,5

x=-3,-4,-5

x=-3,4,5

x= 3, -4, -5

Multiple Choice

Write a polynomial function of least degree with the given zeros.

Multiple Choice

Solve by using Rational Root Theorem:
2x³ - 11x² + 12x + 9 = 0

-1, 1, 3

-1, 3/2, 3

-1/2, 3, 3

-1/2, 1, 3

Multiple Choice

List all the possible rational zeros
h(x) = x³- 5x²+2x+12

1,2,3,4,6,12

1,2,6,12

1,2,3,4,6,12,-1,-2,-3,-4,-6,-12

Multiple Choice

According to the Rational Root Theorem, what are the all possible rational roots?
2x³ - 11x² + 12x + 9 = 0

±1,±2

±1,±3,±9

±1,±3±9,±1/2,±3/2,±9/2

±1,±2,±1/3,±2/3,±1/9,±2/9

Multiple Choice

Which of the following is a COMPLETE list of all possible Rational Zeros?
f(x) = x³ + 2x² - 6x + 8

±1, ±8

±1, ±2, ±4, ±8

±1, ±2, ±4

1, 2, 4, 8

Multiple Choice

Which of these is a possible rational root of the polynomials?

x³ - 6x² - x + 30

-9

-15

Multiple Choice

Find the zeros of the polynomial.
f(x) = (x-5)(2x+3)(7x-4)(x+6)

x = 5, (2/3), 6, (7/4)

x= -5, (3/2), (-4/7), 6

x= 5, (-3/2), (4/7), -6

x= 6, 5, -2/3, -4/7

Multiple Choice

Let f(x) = 4x² -33x -27. Is k = 9 a zero of the function?

yes

Multiple Select

How could you determine if x-2 is a factor of 2x³-5x²+x-2?

Use synthetic division and see if the quotient is even

Ask the person sitting next to me

Use synthetic division and see if the remainder is zero

Flip a coin

Evaluate the polynomial using root from the factor if it is zero

Multiple Choice

If a zero of a polynomial function has multiplicity 4 that means:

The x intercept is at (4, 0)

The graph will "bounce back" at that zero

The graph will "pass through" at that zero

Zeros cannot have multiplicity of 4

Fill in the Blanks

$x^5+3x^2-4x+120$ how many total possible solutions?

Multiple Choice

Find all zeros.

x= 3,1,1/3

x= -3, -1, -1/3

x = -3, 1, 1/3

x = 3, -1, -1/3

Solve by using Rational Root Theorem:
x³ + 3x² - 6x - 8 = 0

-4, -1, 2

-4, -1, ±√2

1, 2, 4

4,-1,√2

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