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Algebraic Manipulation and Absolute Value Equations

Algebraic Manipulation and Absolute Value Equations

Assessment

Presentation

•

Mathematics

•

12th Grade

•

Practice Problem

•

Hard

Created by

Lorrin Boxx

Used 4+ times

FREE Resource

13 Slides • 9 Questions

1

Algebraic Manipulation and Absolute Value Equations

2

media
Intro Questions:
Solving Equations

3

Multiple Choice

If 2x+3=8x−52x+3=8x-5 , then x=x= ?

1

-2

2

−14-\frac{1}{4}

3

14\frac{1}{4}

4

34\frac{3}{4}

5

43\frac{4}{3}

4

Answer explanation:
media

5

Multiple Choice

If 6x+6=36+3x6x+6=36+3x , then x=x= ?

1

95\frac{9}{5}

2

3

3

9

4

10

5

33

6

Answer explanation:
media

7

Multiple Choice

If 3(x+4)+2x=2(x−2)−43\left(x+4\right)+2x=2\left(x-2\right)-4 , then x=x= ?

1

−203-\frac{20}{3}

2

-5

3

−103-\frac{10}{3}

4

2

5

115\frac{11}{5}

8

Answer explanation:
media

9

Multiple Choice

In a certain situation, the maximum height HH , in meters, that a ball bounces is given by the equation H=35F−0.02H=\frac{3}{5}F-0.02 , where FF is the force, in newtons, with which the ball is bounced. What force, in newtons, must be applied for the height to be 0.16 meters?

1

0.1

2

0.2

3

0.3

4

0.4

5

0.5

10

Answer explanation:
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11

Algebraic Manipulation

12

Multiple Choice

If I=PRTI=PRT , then which of the following is an expression for RR in terms of II , PP , and  TT ?

1

IPTIPT

2

I−PTI-PT

3

IPT\frac{I}{PT}

4

PTI\frac{PT}{I}

5

2IPT\frac{2}{IPT}

13

Answer explanation:
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14

Multiple Choice

For all pairs of real numbers NN and PP where N=5P+4N=5P+4 , P=P=  ?

1

N5−4\frac{N}{5}-4

2

N5+4\frac{N}{5}+4

3

5N4\frac{5N}{4}

4

N−45\frac{N-4}{5}

5

N+45\frac{N+4}{5}

15

Answer explanation:
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16

Multiple Choice

If x=3m−4x=3m-4 and y=6−my=6-m , which of the following expresses yy in terms of xx ?

1

y=2x−4y=2x-4

2

y=x+103y=\frac{x+10}{3}

3

y=2+x3y=\frac{2+x}{3}

4

y=x−43y=x-\frac{4}{3}

5

y=14−x3y=\frac{14-x}{3}

17

Answer explanation:
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18

Absolute Value Equations

19

Multiple Choice

Which of the following are solutions to ∣n+3∣=5\left|n+3\right|=5  ?

I. 2

II. -2

III. -8

1

I only

2

III only

3

II and III

4

I and III

5

I, II, and III

20

Answer explanation:
media

21

Multiple Choice

If ∣4−m∣=12\left|4-m\right|=12 , then m = ?

1

16 or 8

2

8 or 0

3

16 or -8

4

0 or -8

5

-16 or -8

22

Answer explanation:
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Algebraic Manipulation and Absolute Value Equations

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