4 (4x² - 5xy)

4x (4x - 5y)

4x² (4 - 5y)

2(duck)

(x²-2)(x-7)

(x²+2)(x-7)

(x²+2)(x+7)

(x²-2)(x+7)

x(x + 6)(x + 3)

x(x + 9)(x + 2)

x(x + 6)

x(x - 6)(x - 3)

1

-1

-4

3

-3

11x+6

11x+12

11x-36

121x-6

(x - 6)(x - 9)

(x + 3)(x + 2)

(x + 3)(x - 2)

(x + 2)(x + 4)

(x + 4)(x - 9)

(x - 4)(x + 9)

(x - 9)(x + 6)

(x + 4)(x + 9)

3(m + 1)(m + 8)

5(m - 3)(m - 6)

2(m - 7)(m + 3)

5(m - 5)(m + 3)

2x(4x²-9)                                    

(4x²+3)(2x-3)

2x(2x+3)(2x-3)

PRIME

(x²+2)(3x+1)

 (x²+2)(3x-1)

(3x³+6x)(x²-2)

none of the aboe

Prime

( 2x - 32y) (2 x + 32y) 

( 2x - 8y) (2 x - 8y) 

( 2x - 8y) (2 x + 8y) 

4b³(b⁴+b²+4b)

4b³(b⁴+4b+5)

4(b⁵+b³+4b²)

4b²(b³+b+4)

(x-1) (x+5) (x-3)

(x-1) (x+5) (x + 3)

(x+1) (x+5) (x-3)

(x+1) (x-5) (x-3)

Yes, (x-2) is a factor. There is a remainder.

No, (x-2) is  not a factor. The remainder is zero.

Yes, (x-2) is a factor. The remainder is zero.

No, (x-2) is  not a factor. There is a remainder. 

$$f\left(x\right)=\left(x-4\right)\left(2x+1\right)\left(x+7\right)$$  

$$f\left(x\right)=\left(x-4\right)\left(2x^2+15x+7\right)$$  

$$f\left(x\right)=2x^2+15x+7$$  

$$f\left(x\right)=\left(2x+1\right)\left(x+7\right)$$  

(a-b)(a²+ab+b²)

(a+b)(a²-ab+b²)

(a-b)(a²-ab+b²)

(a+b)(a²+ab+b²)

(a-b)(a²+ab+b²)

(a+b)(a²-ab+b²)

(a-b)(a²-ab+b²)

(a+b)(a²+ab+b²)

(x + 1)³

(x+1)(x² - x + 1)

(x - 1) (x² + x - 1)

(x + 1)(x² - 2x + 1)

(2x - 1)(4x² + 2x + 1)

(2x + 1)(4x² - 2x + 1)

(2x - 1)(4x² - 2x - 1)

(2x + 1)(4x² +2x + 1)

(3x-4)(9x²+12x+16)

(3x-4)(9x²-12x+16)

(3x+4)(9x²-12x+16)

(3x+4)(9x²+12x+16)

(2x+3)(4x²-6x+9)

(2x-3)(4x²+6x+9)

(2x-3)(4x²+6x-9)

(2x-3)(2x²+6x+9)

64

27

81

16

No

Yes

Yes, getting GCF first

It is a sum of squares