Trig Ratios

The study of square measurements

The study of triangle measurements

The study of mathematics

The study of measurements

The ratio of the the leg ADJACENT to the angle to the HYPOTENUSE

The ratio of the the leg OPPOSITE to the angle to the HYPOTENUSE

The ratio of the the leg OPPOSITE to the angle to the ADJACENT

The ratio of the the leg ADJACENT to the angle to the HYPOTENUSE

The ratio of the the leg OPPOSITE to the angle to the HYPOTENUSE

The ratio of the the leg OPPOSITE to the angle to the ADJACENT

The ratio of the the leg ADJACENT to the angle to the HYPOTENUSE

The ratio of the the leg OPPOSITE to the angle to the HYPOTENUSE

The ratio of the the leg OPPOSITE to the angle to the ADJACENT

$\frac{Adjacent}{Opposite}$

$\frac{Opposite}{Adjacent}$

$\frac{Opposite}{Hypotenuse}$

$\frac{Adjacent}{Hypotenuse}$

$\frac{15}{12}=\frac{5}{4}$

$\frac{12}{15}=\frac{4}{5}$

$\frac{9}{15}$

$\frac{12}{9}=\frac{4}{3}$

$\frac{Adjacent}{Opposite}$

$\frac{Opposite}{Adjacent}$

$\frac{Opposite}{Hypotenuse}$

$\frac{Adjacent}{Hypotenuse}$

$\frac{15}{12}=\frac{5}{4}$

$\frac{12}{15}=\frac{4}{5}$

 $\frac{9}{15}=\frac{3}{5}$ 

$\frac{12}{9}=\frac{4}{3}$

$\frac{Adjacent}{Opposite}$

$\frac{Opposite}{Adjacent}$

$\frac{Opposite}{Hypotenuse}$

$\frac{Adjacent}{Hypotenuse}$

$\frac{15}{12}=\frac{5}{4}$

$\frac{12}{15}=\frac{4}{5}$

$\frac{9}{15}$

$\frac{12}{9}=\frac{4}{3}$

$SOH\rightarrow\ \sin\ A=\frac{Opposite}{Hypotenuse}$

$CAH\rightarrow\ \cos A=\frac{Adjacent}{Hypotenuse}$

$TOA\rightarrow\ \tan\ A=\frac{Opposite}{Adjacent}$

24.3

49.2

27.5

27.8

$SOH\rightarrow\ \sin\ A=\frac{Opposite}{Hypotenuse}$

$CAH\rightarrow\ \cos A=\frac{Adjacent}{Hypotenuse}$

$TOA\rightarrow\ \tan\ A=\frac{Opposite}{Adjacent}$

2.9

3.3

8.1

4.8