Unit 6 Review (Algebra 2)

$$\left(x+7\right)\left(x-7\right)$$

$$\left(x+2\right)\left(x+3\right)$$

$$\left(x+2\right)\left(x+3\right)^2$$

$$\left(x+7\right)\left(x-7\right)\left(x+2\right)\left(x+3\right)$$

2

7

3

0

-2

$$-x^2$$

$$x+1$$

$$2x-3$$

$$\frac{x+1}{2x-3}$$

$$\frac{x-5}{3x}$$

$$\frac{3x}{x-5}$$

$$\frac{x+7}{3x}$$

$$\frac{2}{x+7}$$

$$\frac{3x}{\left(x+6\right)}$$

$$\frac{x}{x+6}$$

$$\frac{x+6}{3}$$

$$\frac{3}{x^2\left(x+6\right)}$$

$$\frac{x}{4y^2}$$

$$\frac{5x+1}{4xy^2}$$

$$\frac{5}{4xy^2}$$

$$\frac{20x^2+y^2}{4xy^2}$$

$$\frac{7x+4}{x+4}$$

$$\frac{8x+28}{x\left(x+4\right)}$$

$$\frac{x\left(x+4\right)}{8}$$

$$\frac{8}{x\left(x+4\right)}$$

$$\frac{3}{x+5}$$

$$\frac{-3x^2+12x-15}{\left(x-5\right)\left(x-3\right)}$$

$$\frac{x^2+17}{\left(x-3\right)\left(x-5\right)}$$

$$\frac{3-3x}{\left(x-3\right)\left(x-5\right)}$$

$$\frac{4\left(x+2\right)}{x\left(x+3\right)}$$

$$\frac{4}{\left(x+3\right)}$$

$$\frac{6\left(x-2\right)}{x+3}$$

$$\frac{\left(x+2\right)\left(x+3\right)}{x}$$

$$y=-\frac{2}{x-4}+3$$

$$y=\frac{4}{x+2}-3$$

$$y=\frac{3}{x-4}-2$$

$$y=-\frac{4}{x-2}-3$$

$$y=\frac{2}{x-4}+1$$

$$y=\frac{3}{x+1}+4$$

$$y=-\frac{1}{x+1}+4$$

$$y=\frac{3}{x-1}+4$$