More Trig Derivatives Lesson

$$f'\left(x\right)=3\sin^2x\cdot\cos^2x-\sin^4x$$

$$f'\left(x\right)=3\sin^6x\cdot\cos^2x$$

$$f'\left(x\right)=-3\sin^3x$$

$$f'\left(x\right)=\cos^4x-\sin^4x$$

$$f'\left(x\right)=24\sin^33x\cdot\cos^33x$$

$$f'\left(x\right)=12\sin3x\cdot\cos3x$$

$$f'\left(x\right)=4\sin^33x+4\cos^33x$$

$$f'\left(x\right)=12\cos3x-12\sin3x$$

$$f'\left(x\right)=3\left(1+\cos3x\right)^2$$

$$f'\left(x\right)=9\left(1+\cos3x\right)\left(\sin3x\right)$$

$$f'\left(x\right)=-3\left(1+\cos3x\right)^2\left(\sin3x\right)$$

$$f'\left(x\right)=-9\left(1+\cos3x\right)^2\left(\sin3x\right)$$

$$y=-2x-\pi$$

$$y=-x+\pi$$

$$y=-2x-2\pi$$

$$y=-x-2\pi$$

$$m=2-\sqrt[]{2}$$

$$m=-2\sqrt[]{2}$$

$$m=0$$

$$m=2+\sqrt[]{2}$$