Completando el TCP

$$2x^2-13x+15=0$$

$$2x^2-13x=+15$$

$$2x^2-13x=-15$$

$$2x^2-13x+15=0$$

$$2\left(x^2-13\right)x=+15$$

$$2\left(x^2-\frac{13}{2}x\right)=-15$$

$$\left(\frac{13}{2}\div2\right)^2$$

$$\left(-\frac{13}{2}\div2\right)^2$$

$$\left(\frac{13}{2}\right)^2$$

$$2\left(x^2-\frac{13}{2}x+\frac{169}{16}\right)=-15+2\left(\frac{169}{16}\right)$$

$$2\left(x^2-\frac{13}{2}x+\frac{169}{2}\right)=-15+2\left(\frac{169}{2}\right)$$

$$2\left(x^2+\frac{13}{2}x-\frac{169}{4}\right)=-15+2\left(\frac{169}{16}\right)$$

$$2\left(x-\frac{13}{4}\right)^2=-15+2\left(\frac{169}{16}\right)$$

$$2\left(x^2+\frac{13}{4}x\right)^2=-15+2\left(\frac{169}{16}\right)$$

$$2\left(x^2+\frac{13}{2}\right)^2=-15+2\left(\frac{169}{16}\right)$$

$$-15+2\left(\frac{169}{16}\right)=\frac{49}{16}$$

$$-15+2\left(\frac{169}{16}\right)=\frac{39}{16}$$

$$-15+2\left(\frac{169}{16}\right)=\frac{49}{8}$$

$$\left(x-\frac{13}{4}\right)^2=\frac{98}{8}$$

$$\left(x-\frac{13}{4}\right)^2=\frac{49}{16}$$

$$\left(x-\frac{13}{4}\right)^2=\frac{49}{8}$$

$$x=\pm\frac{7}{4}-\frac{13}{4}$$

$$x=\pm\frac{13}{4}+\frac{49}{16}$$

$$x=\pm\frac{7}{4}+\frac{13}{4}$$

x1=5

x2=3/2

x1=-5

x2=2/3

x1=-2

x2=-5/4