10.7 Circles in the Coordinate Plane

Write the equation of a circle with center (7, 0) with radius 3. #1

In the equation (x+2)²+(y+3)²=49, the center of the circle is at....#2

#3

Which graph corresponds to

(x)²+ (y-6)²=9? #20

Which graph corresponds to

(x-4)²+ (y+4)²=25? #21

What are the coordinates of the center and the radius of the circle with equation:

(x - 4)² + (y - 3)² = 25 ? #5

What is the equation of the circle, with center (-2,-7) and radius 3 units? #6

What is the equation of the circle, with center (-4,5) and radius 6 units? #7

Change the following equation to standard form

x²+y²-4x+12y-8=0. #4

A circle has the equation x² + y² - 12x + 8y + 3 = 0. Use completing the square to write the equation in standard form. #11

The endpoints of a diameter of a circle are (3,1) and (9,5).Find the equation of the circle? Hint: In this problem, we are not given the center or radius however we can find the length of the diameter using the distance formula and then divide it by 2. The center is simply the midpoint of the given points. $$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$$   $$Use\ Midpoint\ Formula\ to\ find\ the\ center\ \ \left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)$$   #9

The point (3,3) is on a circle whose center is at (-1,3). Write the standard form of the equation of the circle. HINT: USE THE DISTANCE FORMULA TO FIND THE RADIUS $$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$$   #16