Linear Functions

{(1,4), (2, 3), (3, 5)}

{(2, 1), (2,5), (2,6)}

{(-2, -2), (0, -2), (-2, 2)}

{(0, 1), (-2, 1), (0, 3)}

No, since the graph crosses thrice using a vertical line test.

Yes, since its a curved graph.

Yes, since the graph crosses once using a vertical line test.

No, since it has no domain.

$$y\ =\ 3x+2$$

$$f\left(x\right)=-2x$$

$$y=2x^{2\ }+1$$

$$y=7$$

$$y=\frac{2}{x}$$

$$y=-4x$$

$$f\left(x\right)=3x$$

$$f\left(x\right)=4$$

No, since the slope is negative.

No, since the the exponent of x is 2 and not 1.

Yes, since the exponent of the variable is 2.

Yes, since it is written in f(x) form.

Yes, the x-values goes by 1 and the y-values goes by -4.

Yes, the x-values goes by 1 and the y-values goes by 4.

No, since the y-values does not have a constant rate of change.

No, since the x-values does not have a constant rate of change.

Yes, the x-values goes by 1.

Yes, the x-values goes by 1 and the y-values goes by 3.

No, the y-values goes by 3 and 4.

No, the x-values goes by 1.