$$4x^2-1+3x\ =0$$

$$4x^2-1x+3\ =\ 0$$

$$3x^2+4x-1=0$$

$$-x^2+3x+4=0$$

$$4-x^2+x\ =\ 2$$

$$x^2-2x-4\ =\ 0$$

$$x^3+3x+7=0$$

$$x^2=1$$

$$x\ +3x^2+1=0$$

$$x^2-49=0$$

$$-x^2-6x+9=0$$

$$2x^2+2x+6=0$$

$$\frac{-b^2\pm\sqrt{b-4ac}}{2a}$$

$$\frac{b\pm\sqrt{b^2-4ac}}{2a}$$

$$\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

$$\frac{-b\pm\sqrt{b^2+4ac}}{2a}$$

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eine Lösung

zwei Lösungen

keine (reelle) Lösung.

$$x^2+x-1=0$$

$$x^2-49\ =\ 0$$

$$x^2+36\ =\ 0$$

$$2x^2-8x-8\ =\ 0$$

$$\left(x+3\right)^2\ =\ 0$$

$$\left(2x-3\right)^2=0$$

(x-3)(x+3)=0

(3x-9)²=0