

Transversals with equations
Presentation
•
Mathematics
•
8th Grade
•
Hard
Eric Rodriguez
Used 6+ times
FREE Resource
7 Slides • 13 Questions
1
Mr. Rodriguez
2
Multiple Choice
Which two angles are corresponding angles?
8 and 4
7 and 1
3 and 2
3 and 1
3
Multiple Choice
4
Multiple Choice
4) Given the following two parallel lines cut by a transversal.
Which pair of angles represents alternate exterior angles?
∠4 and ∠8
∠7 and ∠5
∠1 and ∠2
∠6 and ∠5
5
Multiple Choice
3) Given the following two parallel lines cut by a transversal.
Which pair of angles represents alternate interior angles?
∠3 and ∠8
∠7 and ∠2
∠7 and ∠8
∠4 and ∠8
6
Fill in the Blanks
What is m∠2?
Type answer...
7
Multiple Select
Which TWO ANGLES are Same Side Interior Angles?
∠4
∠5
∠6
∠1
∠8
8
Multiple Select
Some other angles to identify:
Which two angles are Vertical Angles?
∠1
∠5
∠7
∠4
∠2
9
Corresponding angles are congruent(equal)
Put the two angles equal to each other.
Solve for x.
If needed, find the angle measurement and any other angles too.
With equations
10
Vertical angles are congruent(equal)
Put the two angles equal to each other.
Solve for x.
If needed, find the angle measurement and any other angles too.
With equations
11
Alternate Interior angles are congruent(equal)
Put the two angles equal to each other.
Solve for x.
If needed, find the angle measurement and any other angles too.
With equations
12
Alternate Exterior Angles are congruent(equal)
Put the two angles equal to each other.
Solve for x.
If needed, find the angle measurement and any other angles too.
With equations
13
Same side Interior Angles are supplementary (180).
Put the two angles equal to 180.
Solve for x.
If needed, find the angle measurement and any other angles too.
With equations
14
Same side Exterior Angles are supplementary (180).
Put the two angles equal to 180.
Solve for x.
If needed, find the angle measurement and any other angles too.
With equations
15
Multiple Choice
16
Multiple Choice
17
Multiple Choice
18
Multiple Choice
19
Multiple Choice
20
Multiple Choice
Mr. Rodriguez
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