Turunan Fungsi Aljabar

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$$f'\left(x\right)=2x^3$$  

$$f'\left(x\right)=-2x^{-1}$$  

$$f'\left(x\right)=-2x^{-3}$$  

$$f'\left(x\right)=2x^{-3}$$  

$$f'\left(x\right)=\frac{1}{2}x^{-\frac{1}{2}}=\frac{1}{2\sqrt{x}}$$  

$$f'\left(x\right)=\frac{1}{2}x^{\frac{1}{2}}=\frac{1}{2}\sqrt{x}$$  

$$f\left(x\right)=\frac{1}{2}x^{\frac{3}{2}}=\frac{1}{2}x\sqrt{x}$$  

$$k\ '\ \left(x\right)=-\frac{8}{x^5}$$  

$$k\ '\ \left(x\right)=-8x^5$$  

$$k\ '\ \left(x\right)=\frac{8}{x^5}$$  

$$k\ '\ \left(x\right)=-\frac{3}{x^5}$$  

$$k\ '\ \left(x\right)=-\frac{5}{x^5}$$  

$$\frac{9}{2x^2\sqrt{x}}$$  

$$-\frac{9}{2x^2\sqrt{x}}$$  

$$\frac{8}{2x^2\sqrt{x}}$$  

$$-\frac{8}{2x^2\sqrt{x}}$$  

$$\frac{9}{2x\sqrt{x}}$$  

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$$4x^4+6x^2-14x-8$$  

$$4x^3-6x^2-14x-8$$  

$$4x^3+6x^2-14x$$  

$$5x^4+6x^2+14x$$  

$$x^4-2x^2-14x$$  

$$x^3+x^2–2$$  

$$x^3+2x^2–4$$  

$$2x^3+2x^2–4$$  

$$2x^3+2x^2–4x$$  

$$2x^3+2x^2–4x+1$$  

$$x-x^2$$  

$$x+x^2$$  

$$2x+x^2+1$$  

$$2x-x^2+1$$  

$$2x+x^2$$  

$$-\frac{2}{x^3}-6x\ -\frac{15}{x^4}$$  

$$-\frac{2}{x^3}+6x\ +\frac{15}{x^4}$$  

$$-\frac{2}{x^3}-6x\ +\frac{15}{x^4}$$  

$$\frac{2}{x^3}+6x\ +\frac{15}{x^4}$$  

$$-\frac{1}{x^2}+3x^2-\frac{1}{\sqrt{2x}}$$  

$$\frac{1}{x^2}+x^2-2$$  

$$-x^3+3x^2+\frac{1}{2}\sqrt{2x}$$  

$$\frac{1}{x^2}+3x^2-2$$  

$$\frac{1}{x^2}+3x^2+\frac{1}{2}\sqrt{2x}$$  

$$\frac{-3}{x^2}-\frac{2}{x^3}+\frac{6}{x^4}$$  

$$\frac{3}{x^2}-\frac{2}{x^3}+\frac{6}{x^4}$$  

$$\frac{-3}{x^2}+\frac{2}{x^3}+\frac{6}{x^4}$$  

$$\frac{-3}{x^2}-\frac{2}{x^3}-\frac{6}{x^4}$$  

$$\frac{3}{x^2}+\frac{2}{x^3}+\frac{6}{x^4}$$  

$$h\ '\ \left(t\right)=\frac{1}{3}t^{-\frac{2}{3}}-3\$$  

$$h\ '\ \left(t\right)=\frac{1}{3}t^{-\frac{2}{3}}$$  

$$h\ '\ \left(t\right)=-3\$$  

$$h\ '\ \left(t\right)=\frac{1}{3}t^{ }-3\$$  

$$gatau\ ah\ >\sim<$$  

$$x^5-x^3+3x^2-3$$  

$$5x^4+3x^2+6x$$  

$$5x^4-3x^2+6x$$  

$$5x^4-3x^2-6x$$  

$$x^4-x^2+x$$  

$$f'\left(x\right)=6x^2+14x+3$$  

$$f'\left(x\right)=3x^2+14x+3$$  

$$f'\left(x\right)=6x^2+9x+3$$  

$$f'\left(x\right)=6x^2+14x-3$$  

$$f'\left(x\right)=6x^2-14x+3$$  

$$\frac{-7}{\left(x-4\right)^2}$$  

$$\frac{7}{\left(x-4\right)^2}$$  

$$\frac{-9}{\left(x-4\right)^2}$$  

$$\frac{9}{\left(x-4\right)^2}$$  

$$\frac{-10}{\left(x-4\right)^2}$$  

$$f'\left(x\right)=\frac{-10}{\left(4x+3\right)^2}$$  

$$f'\left(x\right)=\frac{-5}{\left(4x+3\right)^2}$$  

$$f'\left(x\right)=\frac{2}{\left(4x+3\right)^2}$$  

$$f'\left(x\right)=\frac{5}{\left(4x+3\right)^2}$$  

$$f'\left(x\right)=\frac{10}{\left(4x+3\right)^2}$$  

$$-\frac{17}{4}$$  

$$-\frac{15}{4}$$  

$$\frac{6}{4}$$  

$$\frac{15}{4}$$  

$$\frac{17}{4}$$  

$$12\left(3x^2+5\right)^3$$  

$$24x\left(3x^2+5\right)^3$$  

$$12x\left(3x^2+5\right)^3$$  

$$24\left(3x^2+5\right)^3$$  

$$5\left(2x^6+4x^2\right)^4.\left(12x^5+8x\right)$$  

$$5\left(2x^6+4x^2\right)^4$$  

$$5\left(2x^6+4x^2\right)^4\left(12x\right)$$  

$$f'\left(x\right)=\left(4x+6\right)\left(x^2+3x-5\right)$$

$$f'\left(x\right)=\left(2x+3\right)\left(x^2+3x-5\right)$$  

$$f'\left(x\right)=x^2+3x-5$$  

$$\left(4x+3\right)\left(x^2+3x-5\right)$$  

$$\frac{1}{\sqrt{2x+4}}$$  

$$\frac{2}{\sqrt{2x+4}}$$  

$$\frac{-1}{\sqrt{2x+4}}$$  

$$\frac{-2}{\sqrt{2x+4}}$$  

$$\frac{3}{\sqrt{2x+4}}$$  

$$\frac{10x^4-6}{\sqrt{2x^5-6x+1}}$$  

$$\left(10x^4-6\right)\sqrt{2x^5-6x+1}$$  

$$(10x^4–6)\ \left(2x^5+6x\ +1\right)^{\frac{3}{2}}$$  

$$\frac{5x^4-3}{\sqrt{2x^5-6x+1}}$$  

$$\frac{1}{\sqrt{10x^4-6}}$$