CIE Coordinated Science: 7.2 Redox

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Chemistry, Science

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9th - 10th Grade

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Ricardo Echeverria-Valda

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9 Slides • 15 Questions

CIE Coordinated Science: 7.2 Redox

Take a look at your notes from C4 stoichiometry and C5 electricity & chemistry, remind yourself of the following:

Chemical formulae
Ionic charges
OILRIG
Half-equations

CIE Coordinated Science: 7.2 Redox

Page 39 of the CIE 0654 syllabus

CIE Coordinated Science: 7.2 Redox

How to identify redox reactions and how to find the reducing or oxidising agent.

Multiple Choice

When a substance is oxidised it will:

Gain electrons

Gain protons

Lose electrons

Lose protons

Fill in the Blanks

Type answer...

Multiple Choice

The oxidizing agent is the substance that:

Gains protons

Loses protons

Gains electrons

Loses electrons

Fill in the Blanks

Type answer...

Fill in the Blanks

Type answer...

CIE Coordinated Science: 7.2 Redox

1. Assign oxidation numbers (charges) to reactant atom.

Cu = +2

O = -2

H₂ = 0

Copper(II) Oxide - Roman numerals tell us the charge which gives us the oxidation state.

Hydrogen - this is the natural state of H which means the oxidation state = 0.

CIE Coordinated Science: 7.2 Redox

2. Assign oxidation numbers (charges) to product atoms:

Cu = 0

O = -2

H₂ = +1

Copper - elements are always 0.

Hydrogen - is always +1 unless bonded to a metal .

Oxygen - is always -2.

CIE Coordinated Science: 7.2 Redox

3. Compare the oxidation state changes:

Cu: +2 to 0

Reduction - number decreases

H: 0 to +1

Oxidation - number increases

CIE Coordinated Science: 7.2 Redox

4. Identify the reducing and oxidising agents.

Cu: +2 to 0

Reduction - number decreases

This is the OXIDISING AGENT

H: 0 to +1

Oxidation - number increases

This is the REDUCING AGENT

Multiple Choice

Defined as the gain of electrons.

oxidation

redox

reduction

LEO GER

Multiple Choice

Cl₂ + 2e- --> 2Cl ^- is an example of:

a chemical reaction

redox

oxidation

reduction

Multiple Choice

An increase in oxidation number.

more acidic

reduction

less basic

oxidation

Multiple Choice

Substance that oxidises another substance by accepting its electrons.

reducing agent

oxidation number

combustion

oxidising agent

Multiple Choice

Which is the correct half-equation of this reaction: 2Na + Cl₂ --> 2NaCl

Cl₂ + e^- --> 2Cl^-

2Cl - e^- --> Cl₂

Na --> Na⁺ + e^-

Na⁺ + Cl^---> NaCl

Multiple Choice

What is the reducing agent here: N₂ + 3H₂ --> 2NH₃

N₂

H₂

NH₃

2NH₃

Multiple Choice

Substance that reduces another substance by losing electrons.

reducing agent

half-reaction

electronegative atom

oxidizing agent

Multiple Choice

CIE Coordinated Science: 7.2 Redox

Take a look at your notes from C4 stoichiometry and C5 electricity & chemistry, remind yourself of the following:

Chemical formulae
Ionic charges
OILRIG
Half-equations

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