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Lesson 19 Beyond Circles

Lesson 19 Beyond Circles

Assessment

Presentation

Mathematics

8th - 12th Grade

Medium

CCSS
5.G.A.2, HSG.SRT.C.8

Standards-aligned

Created by

Andrew Witczak

Used 5+ times

FREE Resource

10 Slides • 11 Questions

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Lesson 19 Beyond Circles

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Open Ended

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 f(t)=2sin(2πt24)f\left(t\right)=2\sin\left(\frac{2\pi t}{24}\right)  The water level f, in feet, at a certain beach is modeled by the function f(t), where t is the number of hours since the level was measured.


Sketch a graph on the function over the first 72 hours.

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Multiple Choice

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Write an equation describing the vertical position on a Ferris wheel that is the same size as the Ferris wheel described by f but spins twice as quickly.

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g(t)=80sin(2πt15)+95g\left(t\right)=80\sin\left(\frac{2\pi t}{15}\right)+95

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g(t)=80sin(2πt30)+95g\left(t\right)=80\sin\left(\frac{2\pi t}{30}\right)+95

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g(t)=80sin(2πt45)+95g\left(t\right)=80\sin\left(\frac{2\pi t}{45}\right)+95

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g(t)=80sin(2πt60)+95g\left(t\right)=80\sin\left(\frac{2\pi t}{60}\right)+95

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Multiple Choice

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Write an equation describing the vertical position on a Ferris wheel that spins the same speed as the Ferris wheel described by f but whose radius is twice as large.

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 g(t)=160sin(2πt15)+95g\left(t\right)=160\sin\left(\frac{2\pi t}{15}\right)+95 

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 g(t)=160sin(2πt30)+175g\left(t\right)=160\sin\left(\frac{2\pi t}{30}\right)+175 

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 g(t)=160sin(2πt30)+95g\left(t\right)=160\sin\left(\frac{2\pi t}{30}\right)+95 

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g(t)=80sin(2πt60)+95g\left(t\right)=80\sin\left(\frac{2\pi t}{60}\right)+95

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Lesson 19 Beyond Circles

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