Graphing Quadratic Equations

Lets review quadratic equations so far...

Make sure to take some notes...

Step 1: Find the axis of symmetry by x = -b/2a

Step 2: Find the vertex.

Substitute x-value into the equation to obtain the y-value of the vertex.

Step 3: Create a table with coordinate points 2 points on both sides of the line of symmetry.

Remember  $f\left(x\right)=ax^2+bx+c$ .
So using  $x=\frac{-b}{2a}$  , we see that 
a=2, and b=-4 -->    $x=\frac{-\left(-4\right)}{2\left(2\right)}=1$  

Since  $x=\frac{-b}{2a}=1$  , the substitute back into f(x).  So  $f\left(1\right)=2\left(1\right)^2-4\left(1\right)-1=3$  
The vertex (h,k) is (1,-3)

Begin with the vertex as the center point on the table.  
Next find the two points on both sides of the line of symmetry.  (Think on 2 values on the left and the right of symmetry)

Take 2 minutes to discuss with a partner on the next slide and put your answers in the chat and in the lesson.

We will find the line of symmetry, the vertex and the matching graphs of quadratic equations.