HPC Section 4.6 Sec & Csc Day 1

When graphing y = csc x, what will the zeros of y = sin x become?

When graphing y = csc x, where will y = sinx and y = csc x touch?

(In other words, where are sin x and csc x equal?)

Reciprocal Function Graphs

$$\csc x\ =\ \frac{1}{\sin x}$$  

When sin x = 1, what is csc x = ?

Reciprocal Function Graphs

$$\sec x\ =\ \frac{1}{\cos x}$$  

When $$x\ =\ \frac{\pi}{2}$$   what is sec x = ?

Reciprocal Function Graphs

Because

$$\sec x\ =\ \frac{1}{\cos x}$$  and $$\tan x\ =\ \frac{\sin x}{\cos x}$$  

They are undefined at the same places where x = ?

$$y\ =\ 2\sin\ \left(x+\frac{\pi}{4}\right)$$  

What is the amplitude of the graph ?

$$y\ =\ 2\sin\ \left(x+\frac{\pi}{4}\right)$$  

What is the period of the graph ?

$$y\ =\ 2\sin\ \left(x+\frac{\pi}{4}\right)$$  

What is the phase shift of the graph?