Alg Semester 2 Midterm Review

x = 2

x = -18

x = 16

x = -4

True

False

(1,9)

(2,5)

(1,-3)

(2,1)

$$3^5$$  

$$\frac{1}{3^5}$$  

$$\frac{1}{\left(\sqrt{3}\right)^5}$$  

$$\sqrt{3^5}$$  

$$\left(x^3y\right)^3=x^9y^3$$

$$\left(x^4y^2\right)^4=\left(xy\right)^{10}$$

$$\left(\frac{x^2}{y^3}\right)^2=\frac{x^4}{y^6}$$

$$x^4y^2z^0=1$$

$$x^{-15}\cdot x^4=x^{11}$$

$$4\sqrt{3}$$  

$$\sqrt{30}$$  

$$3\sqrt{9}$$  

3

$$\sqrt{7}+\sqrt{175}=6\sqrt{7}$$

$$\sqrt{80}-\sqrt{20}=2\sqrt{5}$$

$$7\sqrt{5}-\sqrt{15}=4\sqrt{5}$$

$$2\sqrt{80}+\sqrt{45}=9\sqrt{5}$$

$$\frac{3\sqrt{30}}{\sqrt{15}}$$  

$$\sqrt{18}$$  

$$3\sqrt{2}$$  

9

$$8x^2y+6xy^2z+9xyz$$

$$2x-x^3-2x^2$$

$$-4xy^3+5x^3+xy+1$$

$$x^5+5x^2y^2+6y^2$$

$$10x^4y^3-12x^3y^2-x^2y+4x$$

$$5x^2+11xy-y^2$$  

$$5x^2-5xy-3y^2$$  

$$3x^2+5xy-y^2$$  

$$3x^2+11xy+3y^2$$  

$$\left(xy^2\right)\left(x^2y\right)=x^2y^2$$

$$7x^3\left(5x-3\right)=\ 35x^4-21x^3$$

$$2x^4\left(-3x^2-6x\right)=\ -5x^6-12x^5$$

$$4x^2\left(5x^2+5xy-7y^2\right)=\ 20x^4+20x^3y-28x^2y^2$$

$$5x^3y\left(x^2-y+3\right)=\ 5x^5-5x^3+15x^3y$$

$$6x^2+13x-2$$  

$$6x^2+x+2$$  

$$2x^2+x-2$$  

$$2x^2+13x-6$$  

(2x+5)(6x +7)

(4x+5)(3x+2)

(-4x+5)(-3x+2)

(6x+4)(2x+3)