
Writing equations of transformations
Presentation
•
Mathematics
•
11th Grade
•
Medium
Karine Ptak
Used 7+ times
FREE Resource
12 Slides • 8 Questions
1
Writing equations of transformations
Please grab paper and pencil for notes
2
Key features of a parabola (review)
Write down on your paper
What are the coordinates of both x-intercepts
What are the coordinates of the vertex
3
Multiple Choice
The coordinate of the vertex are
(1,0)
(5,0)
(3,4)
(0,-4)
4
Multiple Choice
The equation for the axis of symmetry is
x=4
y=3
x=3
y=4
5
This is the graph of the parent function
f(x)=x2What are the coordinates of the vertex?
What is the ARoC on the interval [0,1]?
6
To write the transformation equation of the parent function
f(x)=x2We use (h, k) from the vertex
We use a = the ARoC for the interval from the vertex to the first lattice point on its right
7
To write the transformation equation of the parent function
We use (0, 0) from the vertex
We use a = 1
f(x)=a(x−h)2+k
f(x)=1(x−0)2+0
8
Another example
What are the coordinates of the vertex?
What is the ARoC on the interval?
9
Multiple Choice
Given that the vertex has coordinates (0,0) and the ARoC is a=2, the transformation equation for this graph is:
f(x)=2(x−0)2+0
f(x)=(x−0)2+2
10
Another example
What are the coordinates of the vertex?
What is the ARoC on the interval?
11
Multiple Choice
Given that the vertex has coordinates (0,0) and the ARoC is a=-1, the transformation equation for this graph is:
f(x)=1(x−0)2+0
f(x)=(x−0)2−1
f(x)=−1(x−0)2+0
12
Using (h,k) other than (0,0)
What are the coordinates of the vertex?
What is the ARoC on the interval [1,2]?
13
Multiple Choice
Given that the vertex has coordinates (1,1) and the ARoC is a=1, the transformation equation for this graph is:
f(x)=1(x−1)2+1
f(x)=(x−0)2−1
f(x)=1(x−1)2−1
14
Ramping up
What are the coordinates of the vertex?
What is the ARoC on the interval [3,4]?
15
Multiple Choice
Given that the vertex has coordinates (3,4) and the ARoC is a=1, the transformation equation for this graph is:
f(x)=1(x−4)2+3
f(x)=1(x−3)2+4
f(x)=3(x−4)2−1
16
Ramping up
What are the coordinates of the vertex?
What is the ARoC on the interval [-2,-1]?
17
Multiple Choice
Given that the vertex has coordinates (-2,-1) and the ARoC is a=1, the transformation equation for this graph is:
f(x)=1(x−2)2−1
f(x)=1(x−1)2−2
f(x)=2(x−1)2−1
18
Putting it together
Pay attention to ARoC and Vertex!
19
Putting it together
Your turn
20
Multiple Choice
The transformation equation for this graph is:
f(x)=−3(x−2)2−4
f(x)=−1(x−4)2−2
f(x)=−3(x+2)2−4
Writing equations of transformations
Please grab paper and pencil for notes
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