Pre Calculus Quarter 2 Review

 $f\left(x\right)=\frac{\left(x-3\right)}{\left(2x+9\right)\left(x+10\right)}$  

 $f\left(x\right)=\frac{\left(x-3\right)}{\left(x+1\right)\left(x+10\right)}$  

 $f\left(x\right)=\frac{\left(x-3\right)}{\left(x+2\right)\left(2x+5\right)}$  

This function has no holes.

This function has 1 vertical asymptote.

This function has 1 x-intercept.

This function has 2 vertical asymptotes

This function has 1 hole.

 $\left(-2,\ 0\right)$  

 $\left(-3,\ 0\right)$  

 $\left(3,\ 0\right)$  

 $\left(-\frac{5}{2},\ 0\right)$  

 $x=-2$  

 $x=3$  

 $x=-\frac{5}{2}$  

 $x=-5$  

 $y=0$  

 $y=\frac{1}{2}$  

There is no horizontal asymptote

 $\left(0,0\right)$  

 $\left(0,\ -\frac{3}{10}\right)$  

 $\left(0,\ \frac{1}{2}\right)$  

There is no y-intercept.

The graph has a vertical asymptote at x = 3

The x-intercept is  $\left(\frac{10}{3},\ 0\right)$  

The point  $\left(12,\ 2\right)$ is on the graph. 

The y-intercept is  $\left(0,\ \frac{3}{2}\right)$  

 $y=4^{x-16}$  

 $y=4^x-16$  

 $y=4^{2x}+16$  

 $y=2\cdot4^x-16$  

 $\frac{3}{2}$  

 $6$  

 $\frac{2}{3}$  

 $\frac{1}{6}$  

 $\log_9⁡5+\log_5⁡2$  

 $\log_5⁡9+\log_2⁡5$  

In 17 years, the population is 9.

In 9 years, the population is 17.

In 17 years, the population is 9,000.

In 9 years the population is 17,000.

$\sin\theta=\frac{\sqrt{3}}{2}$

$\sin\theta=1$

$\sin\theta=\frac{\pi}{10}$

$\sin\theta=-\pi$

$y=3\cos\left(2x-\pi\right)+2$

$y=3\cos\left(x+\frac{\pi}{2}\right)+2$

$y=-3\cos\left(x-\pi\right)+2$

$y=3\cos\left(x-\frac{3\pi}{2}\right)+2$