Conics Part 2

$\frac{\left(x+1\right)^2}{25}+\frac{\left(y-2\right)^2}{4}=1$

$\frac{\left(x+1\right)^2}{4}+\frac{\left(y-2\right)^2}{25}=1$

$\frac{\left(x-1\right)^2}{25}+\frac{\left(y+2\right)^2}{4}=1$

$\frac{\left(x-1\right)^2}{4}+\frac{\left(y+2\right)^2}{25}=1$

 $\frac{x^2}{25}+\frac{y^2}{9}\ =\ 1$  

 $\frac{x^2}{25}+\frac{y^2}{16}\ =\ 1$  

 $\frac{x^2}{9}+\frac{y^2}{25}\ =\ 1$  

 $\frac{x^2}{16}+\frac{y^2}{25}\ =\ 1$  

 $\left(\pm\sqrt{29},0\right)$  

 $\left(0,\ \pm\sqrt{29}\right)$  

 $\left(\pm\sqrt{21},0\right)$  

 $\left(0,\ \pm\sqrt{21}\right)$  

(3, 2) up

(3, 2) down

(-3, 2) up

(-3, 2) down

(-3, 2) right

(-3, 2) left

(2, -3) right

(2, -3) left

Up

Down

Left

Right

x = a(y - k)² + h

y = a(x - h)² + k

(1, 0)

(1, -1)

(-1.5, 4)

(-1.5, 0)

3

(3, -1)

6

(6, -1)

1/3

3/4

1/12

-1/12

$x\ =\ \frac{1}{12}\left(y\ +\ 1\right)^2\ +\ 1$

$x\ =\ \frac{1}{12}\left(y\ -\ 1\right)^2\ +\ 1$

$x\ =\ 3\left(y\ -\ 1\right)^2\ +\ 1$

$x\ =\ 3\left(y\ +\ 1\right)^2\ +\ 1$

x = -¹/₈(y - 1)² - 5

y = -¹/₈(x + 1)² - 1

x = ¹/₈(y + 5)² + 1

y = ¹/₈(x + 1)² - 1