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Area of a sector

Area of a sector

Assessment

Flashcard

•

Mathematics

•

8th - 12th Grade

•

Practice Problem

•

Easy

Created by

Wayground Content

Used 2+ times

FREE Resource

Student preview

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the formula to find the area of a sector?

Back

The area of a sector can be calculated using the formula: A=x360×Area of the circle1=x360×πr2A = \frac{x}{360} \times \frac{\text{Area of the circle}}{1} = \frac{x}{360} \times \text{π} r^2 , where x is the central angle in degrees and r is the radius.

2.

FLASHCARD QUESTION

Front

What does the variable 'x' represent in the area of a sector formula?

Back

'x' represents the central angle of the sector in degrees.

3.

FLASHCARD QUESTION

Front

What is the area of a circle with radius r?

Back

The area of a circle is given by the formula: A=πr2A = \text{π} r^2 .

4.

FLASHCARD QUESTION

Front

If the radius of a sector is 10 cm and the central angle is 90 degrees, what is the area of the sector?

Back

Using the formula A=x360×πr2A = \frac{x}{360} \times \text{π} r^2 , we have: A=90360×π×102=14×π×100=25π cm2 (approximately 78.54 cm2)A = \frac{90}{360} \times \text{π} \times 10^2 = \frac{1}{4} \times \text{π} \times 100 = 25\text{π} \text{ cm}^2 \text{ (approximately 78.54 cm}^2) .

5.

FLASHCARD QUESTION

Front

How do you convert the area of a sector from square centimeters to square meters?

Back

To convert from square centimeters to square meters, divide the area in square centimeters by 10,000.

6.

FLASHCARD QUESTION

Front

What is the relationship between the angle of a sector and its area?

Back

The area of a sector is directly proportional to the central angle; as the angle increases, the area of the sector increases.

7.

FLASHCARD QUESTION

Front

If a sector has an area of 15 cm² and a radius of 5 cm, what is the central angle?

Back

Using the formula A=x360×πr2A = \frac{x}{360} \times \text{π} r^2 , we can rearrange to find x: x=A×360πr2=15×360π×52 (approximately 171.89 degrees)x = \frac{A \times 360}{\text{π} r^2} = \frac{15 \times 360}{\text{π} \times 5^2} \text{ (approximately 171.89 degrees)} .

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