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equation of a circle

equation of a circle

Assessment

Flashcard

•

Mathematics

•

10th Grade

•

Practice Problem

•

Hard

•
CCSS
HSG.GPE.A.1, HSG.C.A.2

Standards-aligned

Created by

Wayground Content

FREE Resource

Student preview

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the standard form of the equation of a circle?

Back

The standard form of the equation of a circle is (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2 , where (h, k) is the center and r is the radius.

Tags

CCSS.HSG.GPE.A.1

2.

FLASHCARD QUESTION

Front

What does the center of a circle represent in its equation?

Back

The center of a circle is the point (h, k) in the equation (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2 .

Tags

CCSS.HSG.GPE.A.1

3.

FLASHCARD QUESTION

Front

How do you find the radius of a circle from its equation?

Back

The radius can be found by taking the square root of the right side of the equation in standard form: r=sqrt(r2)r = \text{sqrt}(r^2) .

Tags

CCSS.HSG.GPE.A.1

4.

FLASHCARD QUESTION

Front

What is the radius of a circle with the equation (x−2)2+(y+3)2=16(x - 2)^2 + (y + 3)^2 = 16 ?

Back

The radius is 4, since r2=16r^2 = 16 and r=sqrt(16)=4r = \text{sqrt}(16) = 4 .

Tags

CCSS.HSG.GPE.A.1

5.

FLASHCARD QUESTION

Front

Write the equation of a circle with center (0, 0) and radius 5.

Back

The equation is x2+y2=25x^2 + y^2 = 25 .

Tags

CCSS.HSG.GPE.A.1

6.

FLASHCARD QUESTION

Front

What is the center of the circle represented by the equation (x+1)2+(y−2)2=9(x + 1)^2 + (y - 2)^2 = 9 ?

Back

The center is (-1, 2).

Tags

CCSS.HSG.GPE.A.1

7.

FLASHCARD QUESTION

Front

How do you convert the general form of a circle's equation to standard form?

Back

To convert from general form Ax2+Ay2+Bx+Cy+D=0Ax^2 + Ay^2 + Bx + Cy + D = 0 to standard form, complete the square for x and y.

Tags

CCSS.HSG.GPE.A.1

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