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All 6 Trig Functions

All 6 Trig Functions

Assessment

Flashcard

•

Mathematics

•

10th Grade

•

Practice Problem

•

Hard

•
CCSS
HSG.SRT.C.6, HSF.TF.A.2, HSF.TF.C.8

+3

Standards-aligned

Created by

Wayground Content

Used 1+ times

FREE Resource

Student preview

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15 questions

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1.

FLASHCARD QUESTION

Front

What are the six trigonometric functions?

Back

Sine (sin), Cosine (cos), Tangent (tan), Cosecant (csc), Secant (sec), Cotangent (cot).

Tags

CCSS.HSG.SRT.C.6

2.

FLASHCARD QUESTION

Front

Define Sine (sin) in a right triangle.

Back

Sine is the ratio of the length of the opposite side to the length of the hypotenuse: sin(θ)=oppositehypotenuse\text{sin}(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} .

Tags

CCSS.HSG.SRT.C.6

3.

FLASHCARD QUESTION

Front

Define Cosine (cos) in a right triangle.

Back

Cosine is the ratio of the length of the adjacent side to the length of the hypotenuse: cos(θ)=adjacenthypotenuse\text{cos}(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} .

Tags

CCSS.HSG.SRT.C.6

4.

FLASHCARD QUESTION

Front

Define Tangent (tan) in a right triangle.

Back

Tangent is the ratio of the length of the opposite side to the length of the adjacent side: tan(θ)=oppositeadjacent\text{tan}(\theta) = \frac{\text{opposite}}{\text{adjacent}} .

Tags

CCSS.HSG.SRT.C.6

5.

FLASHCARD QUESTION

Front

What is the relationship between the six trigonometric functions?

Back

The relationships can be expressed as: csc(θ)=1sin(θ),sec(θ)=1cos(θ),cot(θ)=1tan(θ)\text{csc}(\theta) = \frac{1}{\text{sin}(\theta)}, \text{sec}(\theta) = \frac{1}{\text{cos}(\theta)}, \text{cot}(\theta) = \frac{1}{\text{tan}(\theta)} .

Tags

CCSS.HSF.TF.A.2

6.

FLASHCARD QUESTION

Front

What is the Pythagorean Theorem?

Back

In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides: a2+b2=c2a^2 + b^2 = c^2 .

Tags

CCSS.8.G.B.8

7.

FLASHCARD QUESTION

Front

How do you find the value of cotangent (cot)?

Back

Cotangent is the reciprocal of tangent: cot(θ)=1tan(θ)=adjacentopposite\text{cot}(\theta) = \frac{1}{\text{tan}(\theta)} = \frac{\text{adjacent}}{\text{opposite}} .

Tags

CCSS.HSG.SRT.C.6

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