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Six Trigonometric Ratios

Six Trigonometric Ratios

Assessment

Flashcard

•

Mathematics

•

9th Grade

•

Practice Problem

•

Hard

•
CCSS
HSG.SRT.C.6, HSG.SRT.C.7, HSG.SRT.C.8

Standards-aligned

Created by

Wayground Content

FREE Resource

Student preview

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What are the six trigonometric ratios?

Back

The six trigonometric ratios are: 1. Sine (sin) 2. Cosine (cos) 3. Tangent (tan) 4. Cosecant (csc) 5. Secant (sec) 6. Cotangent (cot)

Tags

CCSS.HSG.SRT.C.6

2.

FLASHCARD QUESTION

Front

Define Sine (sin) in a right triangle.

Back

Sine (sin) is the ratio of the length of the opposite side to the length of the hypotenuse. Formula: sin=oppositehypotenuse\text{sin} = \frac{\text{opposite}}{\text{hypotenuse}} .

Tags

CCSS.HSG.SRT.C.6

3.

FLASHCARD QUESTION

Front

Define Cosine (cos) in a right triangle.

Back

Cosine (cos) is the ratio of the length of the adjacent side to the length of the hypotenuse. Formula: cos=adjacenthypotenuse\text{cos} = \frac{\text{adjacent}}{\text{hypotenuse}} .

Tags

CCSS.HSG.SRT.C.6

4.

FLASHCARD QUESTION

Front

Define Tangent (tan) in a right triangle.

Back

Tangent (tan) is the ratio of the length of the opposite side to the length of the adjacent side. Formula: tan=oppositeadjacent\text{tan} = \frac{\text{opposite}}{\text{adjacent}} .

Tags

CCSS.HSG.SRT.C.8

5.

FLASHCARD QUESTION

Front

Define Cosecant (csc) in a right triangle.

Back

Cosecant (csc) is the reciprocal of sine. Formula: csc=1sin=hypotenuseopposite\text{csc} = \frac{1}{\text{sin}} = \frac{\text{hypotenuse}}{\text{opposite}} .

6.

FLASHCARD QUESTION

Front

Define Secant (sec) in a right triangle.

Back

Secant (sec) is the reciprocal of cosine. Formula: sec=1cos=hypotenuseadjacent\text{sec} = \frac{1}{\text{cos}} = \frac{\text{hypotenuse}}{\text{adjacent}} .

Tags

CCSS.HSG.SRT.C.6

7.

FLASHCARD QUESTION

Front

Define Cotangent (cot) in a right triangle.

Back

Cotangent (cot) is the reciprocal of tangent. Formula: cot=1tan=adjacentopposite\text{cot} = \frac{1}{\text{tan}} = \frac{\text{adjacent}}{\text{opposite}} .

Tags

CCSS.HSG.SRT.C.6

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