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Related Rates Flashcard

Related Rates Flashcard

Assessment

Flashcard

•

Mathematics

•

11th - 12th Grade

•

Practice Problem

•

Hard

Created by

Wayground Content

FREE Resource

Student preview

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the formula for the volume of a sphere?

Back

The volume of a sphere is given by the formula: V=43×π×r3V = \frac{4}{3} \times \text{π} \times r^3 , where r is the radius.

2.

FLASHCARD QUESTION

Front

How do you find the rate of change of the volume of a sphere with respect to time?

Back

To find the rate of change of the volume of a sphere, use the formula: dVdt=4πr2drdt\frac{dV}{dt} = 4\text{π}r^2 \frac{dr}{dt} , where drdt\frac{dr}{dt} is the rate of change of the radius.

3.

FLASHCARD QUESTION

Front

What is the formula for the area of a circle?

Back

The area of a circle is given by the formula: A=π×r2A = \text{π} \times r^2 , where r is the radius.

4.

FLASHCARD QUESTION

Front

How do you find the rate of change of the area of a circle with respect to time?

Back

To find the rate of change of the area of a circle, use the formula: dAdt=2πrdrdt\frac{dA}{dt} = 2\text{π}r \frac{dr}{dt} , where drdt\frac{dr}{dt} is the rate of change of the radius.

5.

FLASHCARD QUESTION

Front

What is the relationship between the volume and height of a cone?

Back

The volume of a cone is given by the formula: V=13×π×r2×hV = \frac{1}{3} \times \text{π} \times r^2 \times h , where r is the radius and h is the height.

6.

FLASHCARD QUESTION

Front

How do you find the rate of change of the height of a cone with respect to time?

Back

To find the rate of change of the height of a cone, use the formula: dhdt=−3Vπr2dVdt\frac{dh}{dt} = -\frac{3V}{\text{π}r^2} \frac{dV}{dt} , where dVdt\frac{dV}{dt} is the rate of change of volume.

7.

FLASHCARD QUESTION

Front

What is the formula for the volume of a balloon (sphere)?

Back

The volume of a balloon is given by the formula: V=43×π×r3V = \frac{4}{3} \times \text{π} \times r^3 .

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