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Pythagorean Theorem & Geometric Mean

Pythagorean Theorem & Geometric Mean

Assessment

Flashcard

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Hard

•
CCSS
8.G.B.8, 6.G.A.1, 8.G.B.7

+2

Standards-aligned

Created by

Wayground Content

FREE Resource

Student preview

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the Pythagorean Theorem?

Back

The Pythagorean Theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). It can be expressed as: c2=a2+b2c^2 = a^2 + b^2 .

Tags

CCSS.8.G.B.8

2.

FLASHCARD QUESTION

Front

What is the formula for the geometric mean of two numbers a and b?

Back

The geometric mean of two numbers a and b is given by the formula: Geometric Mean=a×ba+b\text{Geometric Mean} = \frac{\text{a} \times \text{b}}{\text{a} + \text{b}} .

3.

FLASHCARD QUESTION

Front

If a right triangle has legs of length 3 and 4, what is the length of the hypotenuse?

Back

Using the Pythagorean Theorem: c2=32+42=9+16=25c^2 = 3^2 + 4^2 = 9 + 16 = 25 , thus c=5c = 5 .

Tags

CCSS.8.G.B.7

4.

FLASHCARD QUESTION

Front

What is the relationship between the sides of a right triangle?

Back

In a right triangle, the lengths of the sides must satisfy the Pythagorean Theorem: c2=a2+b2c^2 = a^2 + b^2 .

Tags

CCSS.8.G.B.8

5.

FLASHCARD QUESTION

Front

How do you determine if three lengths can form a right triangle?

Back

To determine if three lengths can form a right triangle, check if the square of the longest length equals the sum of the squares of the other two lengths.

Tags

CCSS.8.G.B.8

6.

FLASHCARD QUESTION

Front

What is the value of x if 3x=x4\frac{3}{x} = \frac{x}{4} ?

Back

Cross-multiplying gives: 3×4=x23 \times 4 = x^2 , thus x2=12x^2 = 12 , so x=2√3x = 2\text{√}3 .

Tags

CCSS.HSA.REI.A.2

7.

FLASHCARD QUESTION

Front

What is the altitude of a triangle with a base of 8 and an area of 24?

Back

The area of a triangle is given by: Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} . Thus, 24=12×8×h24 = \frac{1}{2} \times 8 \times h , solving gives h=6h = 6 .

Tags

CCSS.6.G.A.1

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