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Final Long Test for 2nd quarter

Authored by Melanie Cahilig

Mathematics

12th Grade

CCSS covered

Used 4+ times

Final Long Test for 2nd quarter
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30 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Evaluate.

290

278

250

295

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

During a math project, Mia listed several numbers as 2, 4, 6, 8, 10 and then wrote another expression as 2 + 4 + 6 + 8 + 10 to show her solution steps.
Based on her work, which statement correctly explains the difference between the two representations?

Both are sequences because they show a list of numbers in order.

The first is a series, and the second is a sequence because addition is shown.

The first represents a sequence which is listing of terms, while the second represents a series , sum of the terms.

Both are series because they involve consecutive numbers.

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the sum of the first 30 terms of 2 -2 + 2 -2 +2 -2, ... ?

60

2

-2

0

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

It is a sum of a sequence according to rule.

Sequence

Series

Sigma Notation

Sequencing

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A list of numbers or objects in a special order or rule is called a _________.

Sequence

Series

Sigma Notation

Sequencing

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A gardener arranged flower pots in a line following this pattern:
3, 6, 9, 12, …

He decided to find the total number of pots used after 4 rows by adding them all together.

Which of the following correctly shows how the gardener applied the concept of a series?

Writing the pattern as 3, 6, 9, 12 to show the order of terms.

Writing 3 + 6 + 9 + 12 to represent the sum of the terms.

Describing the pattern as “adding 3 each time” without listing terms.

Drawing the flower pots in a geometric shape.

7.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Find the summation notation. (3Y5)+(3Y6)+(3y7)+(3Y8)+(3Y9)+(3Y10)\left(3Y-5\right)+\left(3Y-6\right)+\left(3y-7\right)+\left(3Y-8\right)+\left(3Y-9\right)+\left(3Y-10\right)  

 n=510 3n+Y\sum_{n=5}^{10}\ 3n+Y  

 n=510 3nY\sum_{n=5}^{10}\ 3n-Y  

 n=510 3Yn\sum_{n=5}^{10}\ 3Y-n  

 n=510 3Y+n\sum_{n=5}^{10}\ 3Y+n  

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