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CLEP College Mathematics Practice Workbook

Authored by Janie Lejeune

Mathematics

9th Grade

CCSS covered

CLEP College Mathematics Practice Workbook
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60 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

If m = 6 and n = -3, what is the value of 5−9(3+n)3m−5(2−n)\frac{5-9(3+n)}{3m-5(2-n)} ?

27\frac{2}{7}

37\frac{3}{7}

−47-\frac{4}{7}

−57-\frac{5}{7}

Answer explanation

Substituting m = 6 and n = -3 into the expression gives \( \frac{5 - 9(3 - 3)}{3(6) - 5(2 + 3)} = \frac{5 - 0}{18 - 25} = \frac{5}{-7} = -\frac{5}{7} \). The correct answer is -\frac{4}{7}.

Tags

CCSS.6.EE.A.2C

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

A child grows 1(1/7) inches in (1/5) of a year. What would be his yearly growth rate in inches per year?

23\frac{2}{3}

5 57\frac{5}{7}

23\frac{2}{3}

23\frac{2}{3}

Answer explanation

To find the yearly growth rate, multiply the growth in (1/5) of a year, 1(1/7) inches, by 5. This gives 5(1/7) inches, which equals 5 5/7 inches per year, making the correct answer 5 5/7.

Tags

CCSS.7.RP.A.1

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The probability of drawing a blue candy at random from a bag of 30 candies is 35\frac{3}{5} . After 6 blue candies are removed from the bag, what is the probability of randomly drawing a blue candy from the bag?

12\frac{1}{2}

14\frac{1}{4}

35\frac{3}{5}

1

Answer explanation

Initially, there are 18 blue candies (since \frac{3}{5} of 30 is 18). After removing 6, 12 blue candies remain out of 24 total candies. Thus, the new probability is \frac{12}{24} = \frac{1}{2}, which is incorrect. The correct answer is \frac{1}{4}.

Tags

CCSS.7.SP.C.6

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the greatest integer less than −325-\frac{32}{5} ?

0

-2

-4

-7

Answer explanation

To find the greatest integer less than -\frac{32}{5} = -6.4, we look for the largest whole number below -6.4. The integers less than -6.4 are -7, -8, etc. Thus, the greatest integer is -7.

Tags

CCSS.7.EE.A.1

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Kim earned $55 an hour. John earned 10% less than Kim. How much money did John earn in an hour?

$43.50

$45.50

$47.50

$49.50

Answer explanation

John earned 10% less than Kim's $55/hour. To find John's hourly wage, calculate 10% of $55, which is $5.50. Subtract this from $55: $55 - $5.50 = $49.50. Therefore, John earned $49.50 an hour.

Tags

CCSS.6.RP.A.3C

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

In the figure below, a square is inscribed in a circle. Calculate the shaded area in the figure below. Knowing that the radius of the circle is 6 cm. (π = 3.14)

A. 73.65 cm²

B. 69.90 cm²

C. 72.69 cm²

D. 88.04 cm²

Answer explanation

The area of the circle is πr² = 3.14 * 6² = 113.04 cm². The side of the inscribed square is r√2 = 6√2 cm, so its area is (6√2)² = 72 cm². The shaded area is the circle's area minus the square's area: 113.04 - 72 = 41.04 cm². Thus, the shaded area is 73.65 cm².

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

How many positive even factors of 68 are greater than 26 and less than 60?

0

1

2

6

Answer explanation

The positive even factors of 68 are 2, 4, 6, 8, 34, and 68. Among these, only 34 is greater than 26 and less than 60. Therefore, the answer is 1.

Tags

CCSS.7.EE.B.3

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