¿Cuál de las siguientes afirmaciones es correcta con respecto al número indicado?

El resultado NO pertenece al conjunto de los números reales.

El resultado pertenece al conjunto de los números enteros.

El resultado pertenece al conjunto de los números irracionales.

El resultado pertenece al conjunto de los números reales.

¿Con cuál de las siguientes operaciones obtenemos un número irracional?

Calculando la raíz cuadrada de 2

Raíz Enésima II Medio I.T: quiz de 29 preguntas

29 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

$\sqrt[4]{16}\ =\ ?\$

$\sqrt[4]{2}$

2

$\sqrt[]{2}$

4

2.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

$\left(\sqrt[3]{27}\right)^3$

9

$\left(\sqrt[]{27}\right)^3$

27

3.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

$\sqrt[]{a^3}$ escrito como potencia es :

$a^{\frac{3}{2}}$

$a^{\frac{1}{3}}$

$a^2$

4.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

$3^{\frac{2}{7}}$ escrito como raíz es :

$\sqrt[]{3^7}$

$\sqrt[3]{7}$

$\sqrt[7]{3^2}$

5.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

$\sqrt[3]{\sqrt[]{64}}$ = ?

$\sqrt[6]{64}$

$\sqrt[4]{64}$

4

6.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

$\sqrt[10]{1}$

10

0

1

7.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

$\sqrt[4]{-16}$ Se puede calcular en los números reales.

VERDADERO

FALSO

8.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

$\sqrt[3]{\sqrt[3]{3}}$ expresado como potencia es:

$3^{\frac{3}{3}}$

$3^{\frac{1}{9}}$

$9^2$

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$^3\sqrt{-27}=$

9

3

$-3$

$-9$

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Si $\sqrt{72}=\sqrt{6^2\times2}$ entonces el resultado de esta raíz es

72

$\sqrt{12}$

$6\sqrt{2}$

$2\sqrt{6}$

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Raíz Enésima II° Medio I.T

164 = ? \sqrt[4]{16}\ =\ ?\ 416​ = ?

(273)3\left(\sqrt[3]{27}\right)^3(327​)3

a3\sqrt[]{a^3}a3​ escrito como potencia es :

3273^{\frac{2}{7}}372​ escrito como raíz es :

643\sqrt[3]{\sqrt[]{64}}364​​ = ?

110\sqrt[10]{1}101​

−164\sqrt[4]{-16}4−16​ Se puede calcular en los números reales.

333\sqrt[3]{\sqrt[3]{3}}333​​ expresado como potencia es:

3−27=^3\sqrt{-27}=3−27​=

Si 72=62×2\sqrt{72}=\sqrt{6^2\times2}72​=62×2​ entonces el resultado de esta raíz es

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$\sqrt[4]{16}\ =\ ?\$

$\left(\sqrt[3]{27}\right)^3$

$\sqrt[]{a^3}$ escrito como potencia es :

$3^{\frac{2}{7}}$ escrito como raíz es :

$\sqrt[3]{\sqrt[]{64}}$ = ?

$\sqrt[10]{1}$

$\sqrt[4]{-16}$ Se puede calcular en los números reales.

$\sqrt[3]{\sqrt[3]{3}}$ expresado como potencia es:

$^3\sqrt{-27}=$

Si $\sqrt{72}=\sqrt{6^2\times2}$ entonces el resultado de esta raíz es