14/12/2024 - Array

What is the base address of a one-dimensional array in C?

How do you access the third element of the array int arr[5] = {10, 20, 30, 40, 50}; using a pointer ptr initialized as int *ptr = arr;?

What is the output?

#include <stdio.h>

int main() {

int arr[3] = {100, 200, 300};

int ptr = arr; printf("%d", (ptr + 1));

return 0; }

What is the correct way to declare an array of integer pointers in C?

If int *arr[3] is an array of integer pointers and each pointer points to an integer, how do you access the integer pointed to by the second pointer?