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Segment Relationships in Circles:Assessment

Authored by Rajdeep Kalwani

Mathematics

9th - 12th Grade

Used 1+ times

Segment Relationships in Circles:Assessment
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16 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 2 pts

Media Image

Given the figure ,find the value of x.

3

6

9

12

2.

MULTIPLE CHOICE QUESTION

1 min • 2 pts

Media Image

Use the figure , if SL = 12 , DL = 18 , and SU = 16, find SB.

28.67

22.5

18

12

3.

MULTIPLE CHOICE QUESTION

1 min • 2 pts

Media Image

In the figure , segment BS is tangent to circle T at S. If BC = 8 cm , and CU=10cm, find BS.

12

14

16

10

4.

MULTIPLE CHOICE QUESTION

1 min • 2 pts

What theorem if two chords intersect in the interior of the circle, then the product of the lengths of the segments of the chord is equal to the product of the lengths of the segments of the other chord.

The Intersecting Segments of Chords Power Theorem

The Segments of a Secants Power Theorem

Arc Length

The Tangent Secant Segments Power Theorem

Answer explanation

The Intersecting Segments of Chords Power Theorem states that if two chords intersect in the interior of a circle, then the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.

5.

MULTIPLE CHOICE QUESTION

1 min • 2 pts

Media Image

Given figure 2 at the right, find the measure of segment AL.

8

9

10

11

Answer explanation

Segment AL is equal to the sum of segments AK and KL. Given that AK = 4 and KL = 5, AL = 4 + 5 = 9. Therefore, the measure of segment AL is 9.

6.

MULTIPLE CHOICE QUESTION

1 min • 2 pts

Media Image

What is the value of x in figure 5.

6

36

9

45

Answer explanation

The value of x in figure 5 is 6 as shown in the diagram.

7.

MULTIPLE CHOICE QUESTION

1 min • 2 pts

Media Image

In figure 6, what is the length of segment GA?

6

8

10

12

Answer explanation

In figure 6, segment GA is the hypotenuse of a right triangle with sides of length 6 and 8. Using the Pythagorean theorem (a^2 + b^2 = c^2), GA = sqrt(6^2 + 8^2) = sqrt(36 + 64) = sqrt(100) = 10.

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